If x² +2y+3z? = x² + 2y² + 3z² = x² + 2y3 +3z3 =2, and x₂x3 +2y₂y3 +3z₂z3 = x3X₁ + 2y3V₁ +3Z3Z1 = x₁x₂ +2₁₂ +3Z₁Z2 = 1, X₁ then find the value of x₂ x3 Y₁ Y₂ Y3 Z1 Z2 Z3
If x² +2y+3z? = x² + 2y² + 3z² = x² + 2y3 +3z3 =2, and x₂x3 +2y₂y3 +3z₂z3 = x3X₁ + 2y3V₁ +3Z3Z1 = x₁x₂ +2₁₂ +3Z₁Z2 = 1, X₁ then find the value of x₂ x3 Y₁ Y₂ Y3 Z1 Z2 Z3
ChapterP: Prerequisites
SectionP.3: Polynomials And Special Products
Problem 8ECP: Find the product of x2+3y and x23y.
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Transcribed Image Text:If x² + 2y + 3z7 = x2 + 2y² + 3z2 = x3 + 2y3 + 3z3 = 2, and x₂x3
+ 2y2y3 + 3z2Z3 = X3X1 + 2y3v1 +3Z3Z1 = x1x₂ + 2y1y₂ + 3z₁²₂ = 1,
X1
then find the value of x₂
X3
Y₁
Y2
Y3
Z1
Z2
Z3
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