If we require 194 mL of a 0.125 mol L-1 HCI solution to reach the equivalence point in the titration of 21.8 mL of an aqueous methyl amine, CH3NH2, solution. What are the concentrations of H3O+ and CH3NH3 at the equivalence point? The Ka for the methyl ammonium ion (CH3NH3+) is 2.2 × 10-11 [H3O+] = Number mol L-1 [CH3NH3]= Number mol L-1 Syntax for scientific notation is 1.23 x 104 is 1.23E4 and 1.23 x 104 is 1.23E-4 Section Attempt 1 of 1 Verify

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If we require 194 mL of a 0.125 mol L-1 HCI solution to reach the equivalence point in the titration of 21.8 mL of an aqueous methyl
amine, CH3NH2, solution. What are the concentrations of H3O+ and CH3NH3 at the equivalence point?
The Ka for the methyl ammonium ion (CH3NH3+) is 2.2 × 10-11
[H3O+] = Number
mol L-1
[CH3NH3]= Number
mol L-1
Syntax for scientific notation is 1.23 x 104 is 1.23E4 and 1.23 x 104 is 1.23E-4
Section Attempt 1 of 1
Verify
Transcribed Image Text:If we require 194 mL of a 0.125 mol L-1 HCI solution to reach the equivalence point in the titration of 21.8 mL of an aqueous methyl amine, CH3NH2, solution. What are the concentrations of H3O+ and CH3NH3 at the equivalence point? The Ka for the methyl ammonium ion (CH3NH3+) is 2.2 × 10-11 [H3O+] = Number mol L-1 [CH3NH3]= Number mol L-1 Syntax for scientific notation is 1.23 x 104 is 1.23E4 and 1.23 x 104 is 1.23E-4 Section Attempt 1 of 1 Verify
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