If water is drained from a vertical cylindrical tank by opening a valve at the base, the water will flow fast when the tank is full and slow down as it continues to drain. As it turns out, the rate at which the water level drops is: dy -kVy dt

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Here RK= Runge-Kutta Method. Please show any theoretical calculations (if required) in detail. Provide a MATLAB code ONLY. Please write a discussion for the problem and the code too. Provide screenshots of the code and graph wherever necessary.
If water is drained from a vertical cylindrical tank by opening a valve at the base, the water will
flow fast when the tank is full and slow down as it continues to drain. As it turns out, the rate at
which the water level drops is:
dy
dt
=
-k√y
where k is a constant depending on the shape of the hole and the cross-sectional area of the tank
and drain hole. The depth of the water y is measured in meters and the time t in minutes. If k =
0.06, determine how much the tank can drain in 2 minutes, if the fluid level is initially 3 m. Solve
by applying Fourth-order RK method and plot your results. Use a step of 0.5 minutes.
Transcribed Image Text:If water is drained from a vertical cylindrical tank by opening a valve at the base, the water will flow fast when the tank is full and slow down as it continues to drain. As it turns out, the rate at which the water level drops is: dy dt = -k√y where k is a constant depending on the shape of the hole and the cross-sectional area of the tank and drain hole. The depth of the water y is measured in meters and the time t in minutes. If k = 0.06, determine how much the tank can drain in 2 minutes, if the fluid level is initially 3 m. Solve by applying Fourth-order RK method and plot your results. Use a step of 0.5 minutes.
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