If u lv and v I w then u I w. (True 0 / False O) Rank(B) < m. (True D/ False O) It is impossible to do the eigenvalue decomposition of B. (True O / False O) If -1 is an eigenvalue of A, then 1 is an eigenvalue of A°. (True 0 / False O) If det(A) = 5 then det(A²)=25. (True 0 / False O) If det(A) = 5 then det(5A)=25. (g) (i) ( True O/ False 0) %3D
If u lv and v I w then u I w. (True 0 / False O) Rank(B) < m. (True D/ False O) It is impossible to do the eigenvalue decomposition of B. (True O / False O) If -1 is an eigenvalue of A, then 1 is an eigenvalue of A°. (True 0 / False O) If det(A) = 5 then det(A²)=25. (True 0 / False O) If det(A) = 5 then det(5A)=25. (g) (i) ( True O/ False 0) %3D
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:A is an n x n and B is an n x m matrix, where n + m. Identify the statement as True or False.
yf u e Col(B) and v E Nul(B), then u I v. (True O/ False D)
det(A)dim(Nul(A) = 0. (True D/ False O)
det(A)dim(Col(A)) = 0. (True O/ False O)
If u I v and v I w then u I w. (True O/ False O)
Rank(B) < m. ( True D/ False O)
It is impossible to do the eigenvalue decomposition of B. ( True O/ False O)
If -1 is an eigenvalue of A, then 1 is an eigenvalue of A?. (True D/ False O)
(a)
(b)
(c)
( True D/ False 0)
( True D/ False 0)
If det(A) = 5 then det(A?)=25.
(i)
If det(A) = 5 then det(54)=25.
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