If these conditions are met, the sampling distribution of the proportion will have a normal shape, and ... the mean of the sampling distribution will be p, (i.e., the same value as the population proportion) and p- (1 – p) the standard deviation of the sampling distribution will be , (that's the square root of the n population proportion of success times proportion of failure - also called q - divided by the sample size). Suppose we know that 82% of all people would say the 1st picture is "Tim". That's the population proportion p. If we were to collect many samples of n=100 people and compute the sample proportion (of people who say the 1st picture is "Tim") for each, by how much should these sample proportions vary, on average? Use the above formula, and give your answer as a percentage, rounded to one place after the decimal. Note: p is a proportion, not a percentage, the formula, so you should use p = 0.82, not p = 82%. %

A First Course in Probability (10th Edition)
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ISBN:9780134753119
Author:Sheldon Ross
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Chapter1: Combinatorial Analysis
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If these conditions are met, the sampling distribution of the proportion will have a normal shape, and ..
the mean of the sampling distribution will be p, (i.e., the same value as the population proportion)
and
p- (1
P)
(that's the square root of the
the standard deviation of the sampling distribution will be
population proportion of success times proportion of failure - also called q - divided by the sample size).
Suppose we know that 82% of all people would say the 1st picture is "Tim". That's the population proportion p.
If we were to collect many samples of n=100 people and compute the sample proportion (of people who say the 1st
picture is "Tim") for each, by how much should these sample proportions vary, on average?
Use the above formula, and give your answer as a percentage, rounded to one place after the decimal. Note: p is a
proportion, not a percentage, in the formula, so you should use p = 0.82, not p = 82%.
%
Transcribed Image Text:If these conditions are met, the sampling distribution of the proportion will have a normal shape, and .. the mean of the sampling distribution will be p, (i.e., the same value as the population proportion) and p- (1 P) (that's the square root of the the standard deviation of the sampling distribution will be population proportion of success times proportion of failure - also called q - divided by the sample size). Suppose we know that 82% of all people would say the 1st picture is "Tim". That's the population proportion p. If we were to collect many samples of n=100 people and compute the sample proportion (of people who say the 1st picture is "Tim") for each, by how much should these sample proportions vary, on average? Use the above formula, and give your answer as a percentage, rounded to one place after the decimal. Note: p is a proportion, not a percentage, in the formula, so you should use p = 0.82, not p = 82%. %
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