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If the wire is 2.75 mm in diameter, how much charge moves past a point in the coil during this operation? The resistivity of copper is 1.68x 10-8 N. m.

If the wire is 2.75 mm in diameter, how much charge moves past a point in the coil during this operation? The resistivity of copper is 1.68x 10-8 N. m.

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If the wire is 2.75 mm in diameter, how much charge moves past a point in the coil during this operation? The resistivity of copper is 1.68x10-8 N. m.
Transcribed Image Text:If the wire is 2.75 mm in diameter, how much charge moves past a point in the coil during this operation? The resistivity of copper is 1.68x10-8 N. m.
The magnetic field perpendicular to a single 17.2-cm-diameter circular loop of copper wire decreases uniformly from 0.590 T to zero.
Transcribed Image Text:The magnetic field perpendicular to a single 17.2-cm-diameter circular loop of copper wire decreases uniformly from 0.590 T to zero.
Expert Solution
Step 1

Given data:

  • The diameter of the circular loop is d1=17.2 cm.
  • The change in the magnetic field is dB=0.590 T.
  • The new diameter of the wire is d2=2.75 mm.
  • The resistivity of the copper is ρ=1.68×10-8 Ω·m.

The expression for the emf can be written as:

∆V=A1dBdt∆V=π4d12dBdt∆V=π417.2 cm×10-2 m1 cm2×0.590 Tdt∆V=0.0137 T·m2dt

The length of the wire used in the loop can be calculated as:

L=2πd12L=2π17.2 cm×10-2 m1 cm2L=0.54 m

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