If the systolic blood pressure for a certain group of people has a mean of 125 and a standard deviation of 5, find the percentage of people in the group who willhave the given systolic blood pressure. Assume the random variable is normally distributed.Round the percentage answers to one decimal place.Refer to the table of values Area Under the Standard Normal Distribution) as needed.Part: 0/3Part 1 of 3(a) Above 110The percentage of people in the group who will have a systolic blood pressure above 110 is1%

Let X denotes the blood pressure for certain group with mean 125 and standard deviation 5 We have to…

Answered: If the systolic blood pressure for a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Sketch a standard normal curve and shade the area that lies to the left of a. 2 13, b. 156, c.0, and d.-8. Then determine the area under the standard normal curve that lies in the area of interest for each part Click here to view page 1 of the normal distribution table Click here to view page 2 of the normal distribution table (Round to four decimal places as needed) b. Sketch a standard normal curve and shade the area under the curve that les to the left of -1.56 Choose the correct graph below OA o du B. A 1.56 odb The area to the left of -1.56 (Round to four decimal places as needed) c. Sketch a standard normal curve and shade the area under the curve that lies to the left of 0. Choose the correct graph below O.C. OD a 2
The distribution of heights in a population of women is approximately normal. Sixteen percent of the women have heights less than 62 inches. About 97.5% of the women have heights less than 71 inches. Use the empirical rule to estimate the mean and standard deviation of the heights in this population. Mean: K inches Standard Deviation: inches
00 T R AWM Z. Use the standard normal table to find the z-score that corresponds to the given percentile. If the area is not in the table, use the entry closest to the area. If the area is halfway between two entries, use the z-score halfway between the corresponding z-scores. If convenient, use technology to find the z-score. P72 Cliak to viouno The z-score that corresponds to P72 is (Round to two decimal places as needed.) Enter your answer in the answer box. ?. ll Jeffrey Jones 61 Lea V Stop Video Participants Chat Share Screen Record Reactions Unmute Type here to search 近。 PrtScn Home (口 F1 F2 F3 F4 F5 23 2$ 5. 9- 4. A. B.
The average grade for an exam is 74, the standard deviation is 7 and the grades are curved to follow a normal distribution. Find the probability that a student will get a grade from 81 to 88 Select one: O a. 0.451 b. 0.612 O c. 0.1359 O d. 0.561
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Use the standard normal table to find the z-score that corresponds to the given percentile. If the area is not in the table, use the entry closest to the area. If the area is halfway between two entries, use the z-score halfway between the corresponding z-scores. If convenient, use technology to find the z-score. P18 The z-score that corresponds to P18 is
For a recent 10k run, the finishers are normally distributed with mean 56minutes and standard deviation 10 minutes. Find the ninth decile for the finishing times. The ninth decile is ________ minutes. (Round to two decimal places as needed.)
Use a table of cumulative areas under the normal curve to find the z-score that corresponds to the given cumulative area. If the area is not in the table, use the entry closest to the area. If the area is halfway between two entries, use the z-score halfway between the corresponding z-scores. If convenient, use technology to find the z-score. 0.05 Click to view page 1 of the table. Click to view page 2 of the table. The cumulative area corresponds to the z-score of (Round to three decimal places as needed.) Standard Normal Table (Page 1) Z 0.09 0.08 0.07 0.06 0.05 0.04 0.03 0.02 0.01 0.00 -3.4 0.0002 0.0003 0.0003 0.0003 0.0003 0.0003 0.0003 0.0003 0.0003 0.0003 -3.3 0.0003 0.0004 0.0004 0.0004 0.0004 0.0004 0.0004 0.0005 0.0005 0.0005 - 3.2 0.0005 0.0005 0.0005 0.0006 0.0006 0.0006 0.0006 0.0006 0.0007 0.0007 - 3.1 0.0007 0.0007 0.0008 0.0008 0.0008 0.0008 0.0009 0.0009 0.0009 0.0010 -3.0 | 0.0010 0.0010 0.0011 0.0011 0.0011 0.0012 0.0012 0.0013 0.0013 0.0013 -2.9 0.0014 0.0014 0.0015…
The time to complete an exam is approximately Normal with a mean of 45 minutes and a standard deviation of 4 minutes. The bell curve below represents the distribution for testing times. The scale on the horizontal axis is equal to the standard deviation. Fill in the indicated boxes.. μ-20 μισ μ-36 μ-20 μ μ+o μ=45 σ = 4 μ+20 μ+30
Average number of Facebook friends I mean of 115 and a standard deviation of 4245 individuals are randomly chosen find the first quartile for the average number of Facebook friends
Listed below are time intervals (min) between eruptions of a geyser. The "recent" times are within the past few years, and the "past" times are from 1995. Does it appear that the variation of the times between eruptions has changed? Use a 0.05 significance level. Assume that the two populations are normally distributed. E Click the icon to view the sample data. - X Sample data Identify the test statistic. The test statistic is (Round to two decimal places as needed.) Identify the P-value Recent 79 95 89 75 55 97 66 90 66 86 81 87 Past 92 85 94 99 68 82 89 98 84 98 92 91 The P-value is (Round to three decimal places as needed.) Print Done What is the conclusion for this hypothesis test? O A. Reject Ho. There is sufficient evidence to support the claim that the variation of the times between eruptions has changed. O B. Reject Ho. There is insufficient evidence to support the claim that the variation of the times between eruptions has changed. OC. Fail to reject Hg. There is sufficient…

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