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- The stack that based on linked list has a. Two data attributes b. One data attribute c. No data attributes d. Three data attributesYou will be given a dictionary, where the name of a student will be the key and a list of courses will be the value. Now, you have to take a course name as input until the user gives 'STOP' in the input. Your task is to display the list of the students taken that course after each input. Given Dictionary { 'Mike' : ['CSE110","ENG101','MAT110'], "Simon' : ['CSE111',"PHY111',"MAT110", 'CSE230], "Shawn' : ['CSE110',"ENG101',"MAT120','CSE230'], 'Alice' : ['CSE110',"ENG091','MAT092'] } Sample Input 1 CSE110 МAT110 CSE260 STOP Sample Output 1 [ 'Mike', "Shawn', 'Alice' ] [ 'Mike', "Simon'] [] Explanation 1: Mike, Shawn and Alice are doing CSE110 Mike and Simon are doing MAT110 No student is doing CSE260In pyton: In this lab, you will be building a software application that removes duplicate values from a list.The purpose of the assignment isto gain experience with user-defined functions, forloop and listmanipulation. Start Start of remove duplicate function (numbers: list of numbers) Initialize an empty list as new_list Loop over each of the number of the numbers list If number not in new_list Append number to new_list Return new_list End of remove duplicate functionStart main function Prompt user for list of numbers Call remove duplicate function Print the new list returned by the remove function End of main functionEnd
- of range. 3. Use the method swap that you wrote in Exercise 2 to write a method that reverses the order of the items in a list alist.I have a program that asks for queries. It is based on a CSV file with three columns for a person's name, city, and height. The print statement for City_list gives it a blank. The problem I'm running into is that if I insert a city that isn't in the CSV file, it ends and doesn't transition to other cities. When I do put in the city that is in the list, it prints out the indexes from the file. How can this be revised to ignore off-list cities and work with in-list cities? Example Output: C:\Users\lucas\PycharmProjects\pythonProject3\venv\Scripts\python.exe C:\Users\lucas\Documents\cs1151\ch8\querydata.py Welcome to my query program! What would you like to do? 1) Count how many people in a city: 2) Find the tallest person/people in a city. 0) Quit Option: 1 Which city?Ely The population of Ely is 10 What would you like to do? 1) Count how many people in a city: 2) Find the tallest person/people in a city. 0) Quit Option: 2 Which city?Ely [1, 12, 13, 14, 20, 25, 40, 65, 84, 90]…10 mplete out of question Complete the transform_2d_list() function that takes a single two-dimensional list as a parameter called a_2d_list. The parameter list has m items, where each item is a list with n items. The function returns a new two-dimensional list, where the first item is a list containing all of the first items in the list items of the original list, and the second item is a list containing all of the second items in the list items of the original list and so on. In other words, the two- dimensional list that is returned will have n items, where each item is a list with m items. You can assume that both m and n are at least 1. Some examples of the function being called are shown below. For example: Test a_2d_list = [[1]] print (transform_2d_list (a_2d_list)) a_2d_list = [['a'], ['b']] print (transform_2d_list (a_2d_list)) a_2d_list = [[1, 2], [3, 4]] print(transform 3d lint( Result [[1]] [['a', 'b']] [[1, 3], [2, 4]]
- The for statement defines a list-iterating loop. There will be no end to its operation so long as there are items to process. What, if anything, about this claim is true?A list called parts has already been created and filled with data. It has a length of 5. Write a for loop that prints each value in this list.hdex mplete the following function according to its docstring using a while loop. The lists we test will not all be sho cribed in English. If you fail any test cases, you will need to read the description and make your own test. def smaller_index(items: list[int]) -> int: 3\ Return the index of the first integer in items that is less than its index, 4. or -1 if no such integer exists in items. 6. >>> smaller_index([2, 5, 7, 99, 6]) 7. -1 8 >>> smaller_index([-5, 8, 9, 16]) 9. 10 >>> smaller_index([5, 8, 9, 0, 1, 3]) 11 3 12 for i in range (len(items)): if items [i] < i: 13 14 15 return i 16 return -1 History X Your solution passed 0 out of 6 cases!
- Initialize a list with 15 grades. Input the passing rate and remove in the list those elements that below the passing rate.Write a procedure called check_workday(check_day). The procedure should accept a single word as a parameter. You have been given a list called work_days. The list contains a couple of days that are defined as workdays for this problem. You are required to: check to see if the day passed to the procedure is a workday. If it is a workday print The name of the day, with the following statement on the same line: " is a workday" (see the example outputs) When the day is a Sunday, display the following statement on the next line: "The fee is double because it is Sunday." NB: Only write the procedure. Do not call it. Please refer to the examples below for further clarity. For example: Test Result check_workday("Monday") Monday is a workday check_workday("Sunday") Sunday is a workday The fee is double because it is Sunday. check_workday("Thursday") Thursday is a workdayAnswer properly What type of data is being stored into a list and identify the name of the list being processed. //Create variables//stores data from the dog table in listsvar dogList = getColumn("Dogs", "Name");var breedList = getColumn("Dogs", "Breed Group");var temperamentList = getColumn("Dogs", "Temperament"); var breedGroup = "";var tempGroup = "";var message = "";var message2 = ""; //Filtered listsvar filteredDogList = [];var filteredTemperamentList = []; //Filtered list to filter filteredDogListvar filteredDogList2 = []; //Button to filter the dogs by breed and takes you to the next screen that displays the filtered dogsonEvent("nextButton", "click", function( ) {breedGroup = getText("breedDropdown");setScreen("dogTypesScreen");filter();updateScreen1();}); //Button to sort the filtered dogs by temperament and takes you to the next screen that displays themonEvent("temperamentButton", "click", function( ) {tempGroup =…