If the scores per round of golfers on the PGA tour are approximately normally distributed with mean 66.9 and standard deviation 2.91, what is the probability that a randomly chosen golfer's score is above 64 strokes?

MATLAB: An Introduction with Applications
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Author:Amos Gilat
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Chapter1: Starting With Matlab
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**Question:**

If the scores per round of golfers on the PGA tour are approximately normally distributed with a mean of 66.9 and a standard deviation of 2.91, what is the probability that a randomly chosen golfer's score is above 64 strokes?

**Explanation:**

This problem involves a normal distribution of golfers' scores and requires calculating the probability of a score being above a certain value. Here, we are given:

- Mean (μ) = 66.9
- Standard Deviation (σ) = 2.91

To find the probability of a score above 64, we'll use the Z-score formula:

\[ Z = \frac{(X - \mu)}{\sigma} \]

Where \( X \) is the score we're interested in (64 strokes).
Transcribed Image Text:**Question:** If the scores per round of golfers on the PGA tour are approximately normally distributed with a mean of 66.9 and a standard deviation of 2.91, what is the probability that a randomly chosen golfer's score is above 64 strokes? **Explanation:** This problem involves a normal distribution of golfers' scores and requires calculating the probability of a score being above a certain value. Here, we are given: - Mean (μ) = 66.9 - Standard Deviation (σ) = 2.91 To find the probability of a score above 64, we'll use the Z-score formula: \[ Z = \frac{(X - \mu)}{\sigma} \] Where \( X \) is the score we're interested in (64 strokes).
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