If the current in the 8.0-2 resistor is 0.5 A, what is the magnitude of the potential difference, for C- resistor?| A wwN 162 B

Delmar's Standard Textbook Of Electricity
7th Edition
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Stephen L. Herman
Chapter7: Parallel Circuits
Section: Chapter Questions
Problem 3PP: Using the rules for parallel circuits and Ohmslaw, solve for the missing values....
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3.

### Problem Statement

If the current in the 8.0-Ω resistor is 0.5 A, what is the magnitude of the potential difference for the \( C \)–resistor?

### Diagram Explanation

The diagram depicts an electrical circuit with resistors and a capacitor labeled \( C \). It is organized as follows:

- There are two parallel branches originating from point A.
- The first branch includes a 2 Ω resistor in series with another 2 Ω resistor.
- The second branch includes an 8 Ω resistor, where the current is given as 0.5 A.
- Both branches reconnect before a 16 Ω resistor and then a 4 Ω resistor in series, leading to point B on the circuit.

### Observations and Calculations

Given that the current through the 8 Ω resistor is 0.5 A, you can use Ohm’s Law (V = IR) to find the potential difference across that resistor:
\[ V = I \times R = 0.5 \, \text{A} \times 8.0 \, \Omega = 4.0 \, \text{V} \]

The circuit conditions, connections, and the question about the \( C \)-resistor suggest a deeper analysis of the circuit to find the voltage across the component indicated by \( C \).
Transcribed Image Text:### Problem Statement If the current in the 8.0-Ω resistor is 0.5 A, what is the magnitude of the potential difference for the \( C \)–resistor? ### Diagram Explanation The diagram depicts an electrical circuit with resistors and a capacitor labeled \( C \). It is organized as follows: - There are two parallel branches originating from point A. - The first branch includes a 2 Ω resistor in series with another 2 Ω resistor. - The second branch includes an 8 Ω resistor, where the current is given as 0.5 A. - Both branches reconnect before a 16 Ω resistor and then a 4 Ω resistor in series, leading to point B on the circuit. ### Observations and Calculations Given that the current through the 8 Ω resistor is 0.5 A, you can use Ohm’s Law (V = IR) to find the potential difference across that resistor: \[ V = I \times R = 0.5 \, \text{A} \times 8.0 \, \Omega = 4.0 \, \text{V} \] The circuit conditions, connections, and the question about the \( C \)-resistor suggest a deeper analysis of the circuit to find the voltage across the component indicated by \( C \).
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