If the current in the 8.0-2 resistor is 0.5 A, what is the magnitude of the potential difference, for C- resistor?| A wwN 162 B

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
icon
Related questions
Question

3.

### Problem Statement

If the current in the 8.0-Ω resistor is 0.5 A, what is the magnitude of the potential difference for the \( C \)–resistor?

### Diagram Explanation

The diagram depicts an electrical circuit with resistors and a capacitor labeled \( C \). It is organized as follows:

- There are two parallel branches originating from point A.
- The first branch includes a 2 Ω resistor in series with another 2 Ω resistor.
- The second branch includes an 8 Ω resistor, where the current is given as 0.5 A.
- Both branches reconnect before a 16 Ω resistor and then a 4 Ω resistor in series, leading to point B on the circuit.

### Observations and Calculations

Given that the current through the 8 Ω resistor is 0.5 A, you can use Ohm’s Law (V = IR) to find the potential difference across that resistor:
\[ V = I \times R = 0.5 \, \text{A} \times 8.0 \, \Omega = 4.0 \, \text{V} \]

The circuit conditions, connections, and the question about the \( C \)-resistor suggest a deeper analysis of the circuit to find the voltage across the component indicated by \( C \).
Transcribed Image Text:### Problem Statement If the current in the 8.0-Ω resistor is 0.5 A, what is the magnitude of the potential difference for the \( C \)–resistor? ### Diagram Explanation The diagram depicts an electrical circuit with resistors and a capacitor labeled \( C \). It is organized as follows: - There are two parallel branches originating from point A. - The first branch includes a 2 Ω resistor in series with another 2 Ω resistor. - The second branch includes an 8 Ω resistor, where the current is given as 0.5 A. - Both branches reconnect before a 16 Ω resistor and then a 4 Ω resistor in series, leading to point B on the circuit. ### Observations and Calculations Given that the current through the 8 Ω resistor is 0.5 A, you can use Ohm’s Law (V = IR) to find the potential difference across that resistor: \[ V = I \times R = 0.5 \, \text{A} \times 8.0 \, \Omega = 4.0 \, \text{V} \] The circuit conditions, connections, and the question about the \( C \)-resistor suggest a deeper analysis of the circuit to find the voltage across the component indicated by \( C \).
Expert Solution
steps

Step by step

Solved in 2 steps with 5 images

Blurred answer
Knowledge Booster
KVL and KCL
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, electrical-engineering and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
Electrical Engineering
ISBN:
9780133923605
Author:
Robert L. Boylestad
Publisher:
PEARSON
Delmar's Standard Textbook Of Electricity
Delmar's Standard Textbook Of Electricity
Electrical Engineering
ISBN:
9781337900348
Author:
Stephen L. Herman
Publisher:
Cengage Learning
Programmable Logic Controllers
Programmable Logic Controllers
Electrical Engineering
ISBN:
9780073373843
Author:
Frank D. Petruzella
Publisher:
McGraw-Hill Education
Fundamentals of Electric Circuits
Fundamentals of Electric Circuits
Electrical Engineering
ISBN:
9780078028229
Author:
Charles K Alexander, Matthew Sadiku
Publisher:
McGraw-Hill Education
Electric Circuits. (11th Edition)
Electric Circuits. (11th Edition)
Electrical Engineering
ISBN:
9780134746968
Author:
James W. Nilsson, Susan Riedel
Publisher:
PEARSON
Engineering Electromagnetics
Engineering Electromagnetics
Electrical Engineering
ISBN:
9780078028151
Author:
Hayt, William H. (william Hart), Jr, BUCK, John A.
Publisher:
Mcgraw-hill Education,