If the crate is given a slight push down the ramp, initially with a speed of 0.75 m/s, what will be the final speed(in m/s) right before it reaches the bottom?Hintm/sNeed Help?Read It Solve for vCrate Sliding Down a RampA 4.50 kg crate slides down a ramp. The ramp is 1.80 m in length and inclined at an angle of 25.0° as shown inthe figure. The crate starts from rest at the top, experiences a constant friction force of magnitude 4.50 N, andcontinues to move a short distance on the horizontal floor after it leaves the ramp.(1) vf =A crate slides down a ramp under the influence of gravity.The potential energy of the system decreases, whereas thekinetic energy increases.V = 0Substitute numerical values to calculate the speed (in m/s):V, =m/s(b) How far does the crate slide on the horizontal floor if it continues to experience a friction force ofdmagnitude 4.50 N?Analyze This part of the problem is handled in exactly the same way as part (a), but in this case we canconsider the mechanical energy of the system to consist only of kinetic energy because the potentialenergy of the system ---Select---v.(Use the following as necessary: g, f, v, and m.)(a) Use energy methods to determine the speed of the crate at the bottom of the ramp.Write the conservation of energy equation for this situation:SOLUTIONΔΚ+ ΔΕ 0Substitute for the energies:Conceptualize Imagine the crate sliding down the ramp in the figure. The larger the friction force, the---Select--- v the crate will slide.0-Categorize We identify the crate, the surface, and the Earth as an isolated system with a---Select---v force acting.Analyze Because v, = 0, the initial kinetic energy of the system when the crate is at the top of the rampis zero. If the y coordinate (in m) is measured from the bottom of the ramp (the final position of thecrate, for which we choose the gravitational potential energy of the system to be zero) with the upwarddirection being positive, then y, =0 = p*j +m.Solve for the distanceand substitute numerical values to calculate its numerical value (in m):(Use the following as necessary: f, m, d, g, and y.)mv?d = =Write the conservation of energy equation for this system:2f,ΔΚ + ΔυU + ΔΕ, -0Finalize For comparison, you may want to calculate the speed of the crate at the bottom of the ramp inthe case in which the ramp is frictionless. Also notice that the increase in internal energy of the systemJ. This energy is shared between the crateSubstitute for the energies:(in J) as the crate slides down the ramp is fd =and the surface, each of which is a bit warmer than before.Gm² - 0) • (0 -Also notice that the distance d the object slides on the horizontal surface is infinite if the surface isfrictionless. Is that consistent with your conceptualization of the situation?EXERCISE

Given,The mass of the crate, m = 4.5 kgThe length of the ramp, L = 1.8 mThe ramp inclined at an…

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If the crate is given a slight push down the ramp, initially with a speed of 0.75 m/s, what will be (in m/s) right before it reaches the bottom? Hint m/s