If the average temperature in degree in a city can be modeled with the formula: f (x)= 26sin(0.48x-1.84)+47 Where x is the month of the year (January corresponds to x-1, etc.) During which month is the average temperature 73° F? The average temporature 73° F = F(x) %3D Get 73=i20 5in(o.48*-):84)+47 2u sin (0.48x- 1.84) =26ie %3D Sim(o48x - 1.84)=} -/ Sin li) o.48 - 1.84. = D.4%x = 1. %4.+
If the average temperature in degree in a city can be modeled with the formula: f (x)= 26sin(0.48x-1.84)+47 Where x is the month of the year (January corresponds to x-1, etc.) During which month is the average temperature 73° F? The average temporature 73° F = F(x) %3D Get 73=i20 5in(o.48*-):84)+47 2u sin (0.48x- 1.84) =26ie %3D Sim(o48x - 1.84)=} -/ Sin li) o.48 - 1.84. = D.4%x = 1. %4.+
Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE:
1. Give the measures of the complement and the supplement of an angle measuring 35°.
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![If the average temperature in degree in a city can be modeled with the formula:
f (x)= 26sin(0.48x-1.84)+47
Where x is the month of the year (January corresponds to x-1, etc.)
During which month is the average temperature 73° F?
The average temporature
73° F = F(x)
%3D
Get
73=i20 5in(o.48*-):84)+47
2u sin (0.48x- 1.84) =26ie
%3D
Sim(o48x - 1.84)=} -/
Sin li)
o.48 - 1.84. =
D.4%x = 1. %4.+](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5e4013eb-babb-4770-9243-fb3338b3d4a1%2F6832cf5d-8a24-4077-baf6-f43e46e354d1%2F7adcxiog.jpeg&w=3840&q=75)
Transcribed Image Text:If the average temperature in degree in a city can be modeled with the formula:
f (x)= 26sin(0.48x-1.84)+47
Where x is the month of the year (January corresponds to x-1, etc.)
During which month is the average temperature 73° F?
The average temporature
73° F = F(x)
%3D
Get
73=i20 5in(o.48*-):84)+47
2u sin (0.48x- 1.84) =26ie
%3D
Sim(o48x - 1.84)=} -/
Sin li)
o.48 - 1.84. =
D.4%x = 1. %4.+
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