1. If the atmospheric pressure is 101.3 kPa and the absolute pressureat the bottom of the tank as shown in the figure is 251.3 kPa.Unit weight of water is equal to 9.79 kN/m?a. What is the specific gravity of the olive oil?b. What is the absolute pressure at the interface of the olive oiland the mercury?c. What is the gage pressure at the interface of the olive oil andthe mercury?15mSAE 30 oilWater25mOlive oil29mМercury04m

Given: The atmospheric pressure is 101.3 kPa. The absolute pressure at the bottom is 251.3 kPa. The…

Answered: If the atmospheric pressure is 101.3…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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1. If the atmospheric pressure is 101.3 kPa and the absolute pressure at the bottom of the tank as shown in the figure is 231.3 kPa Sea Oil (0.89) 1.3 m Water 2.5 m Olive Oil ( SG) 3.0m Mercury (13.6) 0.5 m a. What is the specific gravity of olive oil? b. Gage Pressure at the interface of olive oil and mercury. c. Absolute Pressure at the interface of olive oil and meraury. 2. For the manometer shown, determine the pressure at the center of the pipe. Mercury, s 13.55 1.5 m Yoi, s = 0.80
A tank initially contains 200 gallons of water in which 50 lbs of salt are dissolved. A salt solution containing 0.5 lb of salt per gallon is poured into the tank at a rate of 1 gal/min. The mixture in the tank is stirred and drained off at the rate of 2 gal/min. a) Find the amount of salt in the tank until the tank is empty. b) Find the concentration of salt in the tank until the tank is empty. Where: x (t) = amount of substance dissolve in the solution at any time t ri = container SHOW FBD flow rate of the solution coming in the C₁ = concentration of the solution coming into the container dx dt ro = flow rate of the solution coming out from the container Co = concentration of the solution coming out from the container || r¡Ci - roCo
The pressure on a closed tank reads 58.86 kPa. What is the equivalent height in water? a. b. What is the equivalent height in terms of oil having a specific gravity of 0.85? C. What is the equivalent height in terms of mercury having a specific gravity of 13.6?
The pressure in a gas tank is 2.75 atmospheres. Compute the pressure in (a) psi (lb/in2 ), and (b) kPa. Use 1 atmosphere = 14.7 psi = 101.325 kPa
Two pressure tanks are built one inside the other as shown in the figure. A Bourdon gauge M is connected to the inner tank reads 20 kPa. Another Bourdon gauge N connected to the M outer tank reads 35 kPa. An aneroid barometer reads 750 mm of mercury. Calculate the absolute pressure recorded at Mand N mm in of mercury.
In a manometer shown, the fluid from A to B is mercury (sp. gr. = 13.6) and fromB to C, the fluid is oil (sp. gr. = 0.80). At what height, h, of oil will give a pressureof 452 grams/cm2at C. Use density of water of 1.0 grams per cu.cm.

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