If the air temperature isthe same as the temperature of your skin (about 30°C), your body cannotget rid of heat by transferring it to the air. In that case, it gets ridof the heat by evaporating water (sweat). During bicycling, a typical70 kg person’s body produces energy at a rate of about 500 W due tometabolism, 80% of which is converted to heat. (a) How many kilogramsof water must the person’s body evaporate in an hour to get ridof this heat? The heat of vaporization of water at body temperature is2.42 * 10^6 J/kg. (b) The evaporated water must, of course, be replenished,or the person will dehydrate. How many 750 mL bottles of watermust the bicyclist drink per hour to replenish the lost water? (Recall thatthe mass of a liter of water is 1.0 kg.)

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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If the air temperature is
the same as the temperature of your skin (about 30°C), your body cannot
get rid of heat by transferring it to the air. In that case, it gets rid
of the heat by evaporating water (sweat). During bicycling, a typical
70 kg person’s body produces energy at a rate of about 500 W due to
metabolism, 80% of which is converted to heat. (a) How many kilograms
of water must the person’s body evaporate in an hour to get rid
of this heat? The heat of vaporization of water at body temperature is
2.42 * 10^6 J/kg. (b) The evaporated water must, of course, be replenished,
or the person will dehydrate. How many 750 mL bottles of water
must the bicyclist drink per hour to replenish the lost water? (Recall that
the mass of a liter of water is 1.0 kg.)

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