If the accompanying drawing of an electrochemical cell represents an iron-nickel cell, use the partial activity series included to select the half-reaction represented by the left side of the cell. Element Half-Reaction Lithium Li + Li* + e" Potassium K→K* + e- Barium Ва — Ва* + 2 е- Calcium Са— Са" + 2 е‑ Magnesium Mg → Mg²* + 2 e- Al A* + 3 e Zn→ Zn?* + 2 e" Aluminum Zinc Chromium Cr- Cr* + 3 e Iron Fe → Fe* + 2 e- Co - Co* + 2 e- NI → N?* + 2 e Cobalt Nickel Tin Sn- Sn2* + 2 e Pb → Pb?* + 2 e- Lead Hydrogen H2 →2 H* + 2 e" Cu → Cu?+ + 2 e- Ag → Ag* + e Pt → Pt2+ + 2 e- Copper Silver Platinum Gold Au - Au* + e O A) Ni --> Ni2+ + 2e¯ O B) Fe --> Fe2+ + 2e O C) Fe2+ + 2e" --> Fe O D) Ni2+ + 2e --> Ni Reducing strength
If the accompanying drawing of an electrochemical cell represents an iron-nickel cell, use the partial activity series included to select the half-reaction represented by the left side of the cell. Element Half-Reaction Lithium Li + Li* + e" Potassium K→K* + e- Barium Ва — Ва* + 2 е- Calcium Са— Са" + 2 е‑ Magnesium Mg → Mg²* + 2 e- Al A* + 3 e Zn→ Zn?* + 2 e" Aluminum Zinc Chromium Cr- Cr* + 3 e Iron Fe → Fe* + 2 e- Co - Co* + 2 e- NI → N?* + 2 e Cobalt Nickel Tin Sn- Sn2* + 2 e Pb → Pb?* + 2 e- Lead Hydrogen H2 →2 H* + 2 e" Cu → Cu?+ + 2 e- Ag → Ag* + e Pt → Pt2+ + 2 e- Copper Silver Platinum Gold Au - Au* + e O A) Ni --> Ni2+ + 2e¯ O B) Fe --> Fe2+ + 2e O C) Fe2+ + 2e" --> Fe O D) Ni2+ + 2e --> Ni Reducing strength
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
![If the accompanying drawing of an electrochemical cell represents an iron-nickel cell,
use the partial activity series included to select the half-reaction represented by the
left side of the cell.
Element
Half-Reaction
Lithium
Li Lit + e
Potassium
KK* + e
Ва — Ва* + 2 е
Са — Са2* + 2 е-
Magnesium Mg → Mg2+ + 2 e-
Al → A* + 3 e
Zn- Zn?* + 2 e
Barium
Calcium
Aluminum
Zinc
Chromium
Cr- Cr+ + 3 e-
Iron
Fe → Fe2+ + 2 e-
Со — Со2* + 2 е-
Ni - NI2+ + 2 e
Cobalt
Nickel
Tin
Sn→ Sn2+ + 2 e-
Lead
Pb → Pb2+ + 2 e-
Hydrogen
H2 →2 H* + 2 e
Copper
Cu → Cu2+ + 2 e
Silver
Ag → Ag* + e
Platinum
Pt → Pt2+ + 2 e-
Gold
Au → Aut + e
O A) Ni --> Ni2+ + 2e
B) Fe --> Fe2+ + 2e
O C) Fe2+ + 2e --> Fe
O D) Ni2+ + 2e¯ --> Ni
Reducing strength](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe868d9b8-2cad-4f26-8fe6-2dfbd223072b%2F69b25433-feec-42ba-b395-ccdc5e8774aa%2Fcsdb1bt_processed.png&w=3840&q=75)
Transcribed Image Text:If the accompanying drawing of an electrochemical cell represents an iron-nickel cell,
use the partial activity series included to select the half-reaction represented by the
left side of the cell.
Element
Half-Reaction
Lithium
Li Lit + e
Potassium
KK* + e
Ва — Ва* + 2 е
Са — Са2* + 2 е-
Magnesium Mg → Mg2+ + 2 e-
Al → A* + 3 e
Zn- Zn?* + 2 e
Barium
Calcium
Aluminum
Zinc
Chromium
Cr- Cr+ + 3 e-
Iron
Fe → Fe2+ + 2 e-
Со — Со2* + 2 е-
Ni - NI2+ + 2 e
Cobalt
Nickel
Tin
Sn→ Sn2+ + 2 e-
Lead
Pb → Pb2+ + 2 e-
Hydrogen
H2 →2 H* + 2 e
Copper
Cu → Cu2+ + 2 e
Silver
Ag → Ag* + e
Platinum
Pt → Pt2+ + 2 e-
Gold
Au → Aut + e
O A) Ni --> Ni2+ + 2e
B) Fe --> Fe2+ + 2e
O C) Fe2+ + 2e --> Fe
O D) Ni2+ + 2e¯ --> Ni
Reducing strength
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