Consider a spontaneous concentration cell based on the following half-reactions (where "a" stands for anode and "c" stands for cathode): Fe2+ (aq, c) + 2 e¯ → Fe (s, c) (aq, a) + 2 e- What is the cell voltage (in V) at 298 K if [Fe2*]a = 0.08 M and [Fe2+]c = 1 M? Fe (s, a) → Fe2+ 0.065 V 0.000 V 0.032 V -0.032 V

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Consider a spontaneous concentration cell based on the following half-reactions (where "a" stands for anode and "c" stands
for cathode):
Fe2+(ag, c) + 2 e¯ → Fe (s, c)
Fe (s, a)
→ Fe2+
(aq, a)
+ 2 e-
What is the cell voltage (in V) at 298 K if [Fe2*]a = 0.08 M and [Fe2+]c = 1 M?
%3D
%3D
0.065 V
0.000 V
0.032 V
-0.032 V
Transcribed Image Text:Consider a spontaneous concentration cell based on the following half-reactions (where "a" stands for anode and "c" stands for cathode): Fe2+(ag, c) + 2 e¯ → Fe (s, c) Fe (s, a) → Fe2+ (aq, a) + 2 e- What is the cell voltage (in V) at 298 K if [Fe2*]a = 0.08 M and [Fe2+]c = 1 M? %3D %3D 0.065 V 0.000 V 0.032 V -0.032 V
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