If S is a subring of a ring R, then S[a] is a subring of R[x]. Exercise 2.35.1 Prove this assertion! In particular, this shows that Q[x] is a subring of R[r], which in turn is a subring of C[r].

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abstract algebra

**Example 2.35**

If \( S \) is a subring of a ring \( R \), then \( S[x] \) is a subring of \( R[x] \).

**Exercise 2.35.1**

Prove this assertion!

In particular, this shows that \( \mathbb{Q}[x] \) is a subring of \( \mathbb{R}[x] \), which in turn is a subring of \( \mathbb{C}[x] \).
Transcribed Image Text:**Example 2.35** If \( S \) is a subring of a ring \( R \), then \( S[x] \) is a subring of \( R[x] \). **Exercise 2.35.1** Prove this assertion! In particular, this shows that \( \mathbb{Q}[x] \) is a subring of \( \mathbb{R}[x] \), which in turn is a subring of \( \mathbb{C}[x] \).
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