If P(Aº) =0.4 P(B | A) =0.30 and P(B© | A°) =0.1 P(A U Bº) is .74 .64 .56 .48

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### Probability Problem for Educational Website

**Problem Statement:**

Given the following probabilities:

- \( P(A^c) = 0.4 \)
- \( P(B \mid A) = 0.30 \)
- \( P(B^c \mid A^c) = 0.1 \)

Find the value of \( P(A \cup B^c) \).

**Options:**

- A) 0.74
- B) 0.64
- C) 0.56
- D) 0.48

**Explanation of Probabilities and Terms:**

1. \( P(A^c) \) denotes the probability that event \( A \) does not occur.
2. \( P(B \mid A) \) denotes the conditional probability that event \( B \) occurs given that event \( A \) has occurred.
3. \( P(B^c \mid A^c) \) denotes the conditional probability that event \( B \) does not occur given that event \( A \) has not occurred.
4. \( P(A \cup B^c) \) represents the probability that either event \( A \) occurs or event \( B \) does not occur (or both).

**Solution Approach:**
To calculate \( P(A \cup B^c) \), we use the following formula:

\[ P(A \cup B^c) = 1 - P(A^c \cap B) \]

Firstly, determine the probability \( P(A^c \cap B) \):

\[ P(A^c \cap B) = P(B \mid A^c) \cdot P(A^c) \]

However, we have \( P(B^c \mid A^c) \), thus:

\[ P(B \mid A^c) = 1 - P(B^c \mid A^c) = 1 - 0.1 = 0.9 \]

Therefore, 

\[ P(A^c \cap B) = 0.9 \cdot 0.4 = 0.36 \]

Now, calculate \( P(A \cup B^c) \):

\[ P(A \cup B^c) = 1 - P(A^c \cap B) = 1 - 0.36 = 0.64 \]

**Correct Answer:**

- B) 0.64

This detailed
Transcribed Image Text:### Probability Problem for Educational Website **Problem Statement:** Given the following probabilities: - \( P(A^c) = 0.4 \) - \( P(B \mid A) = 0.30 \) - \( P(B^c \mid A^c) = 0.1 \) Find the value of \( P(A \cup B^c) \). **Options:** - A) 0.74 - B) 0.64 - C) 0.56 - D) 0.48 **Explanation of Probabilities and Terms:** 1. \( P(A^c) \) denotes the probability that event \( A \) does not occur. 2. \( P(B \mid A) \) denotes the conditional probability that event \( B \) occurs given that event \( A \) has occurred. 3. \( P(B^c \mid A^c) \) denotes the conditional probability that event \( B \) does not occur given that event \( A \) has not occurred. 4. \( P(A \cup B^c) \) represents the probability that either event \( A \) occurs or event \( B \) does not occur (or both). **Solution Approach:** To calculate \( P(A \cup B^c) \), we use the following formula: \[ P(A \cup B^c) = 1 - P(A^c \cap B) \] Firstly, determine the probability \( P(A^c \cap B) \): \[ P(A^c \cap B) = P(B \mid A^c) \cdot P(A^c) \] However, we have \( P(B^c \mid A^c) \), thus: \[ P(B \mid A^c) = 1 - P(B^c \mid A^c) = 1 - 0.1 = 0.9 \] Therefore, \[ P(A^c \cap B) = 0.9 \cdot 0.4 = 0.36 \] Now, calculate \( P(A \cup B^c) \): \[ P(A \cup B^c) = 1 - P(A^c \cap B) = 1 - 0.36 = 0.64 \] **Correct Answer:** - B) 0.64 This detailed
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