Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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![**Mathematics Problem: Parallelogram Properties**
Given the equations:
\[ ON = 7x - 5 \]
\[ LM = 6x + 3 \]
\[ NM = x - 4 \]
\[ OL = 2y + 5 \]
**Problem:**
Find the values of \( x \) and \( y \) given that LMNO is a parallelogram.
**Solution:**
To find the values of \( x \) and \( y \), we use the property that in a parallelogram, opposite sides are equal in length.
Therefore, we have:
1. \( ON = LM \)
2. \( NM = OL \)
From the first pair of equations:
\[ 7x - 5 = 6x + 3 \]
Solving for \( x \):
\[ 7x - 6x = 3 + 5 \]
\[ x = 8 \]
From the second pair of equations:
\[ x - 4 = 2y + 5 \]
Substitute \( x = 8 \):
\[ 8 - 4 = 2y + 5 \]
\[ 4 = 2y + 5 \]
Solving for \( y \):
\[ 4 - 5 = 2y \]
\[ -1 = 2y \]
\[ y = -\frac{1}{2} \]
Thus, the values are \( x = 8 \) and \( y = -\frac{1}{2} \).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F753ca653-1c36-4e0c-a51d-824c611dbd4e%2F3936da30-fe39-4db4-9848-082e707f2146%2Fg83bj2w.jpeg&w=3840&q=75)
Transcribed Image Text:**Mathematics Problem: Parallelogram Properties**
Given the equations:
\[ ON = 7x - 5 \]
\[ LM = 6x + 3 \]
\[ NM = x - 4 \]
\[ OL = 2y + 5 \]
**Problem:**
Find the values of \( x \) and \( y \) given that LMNO is a parallelogram.
**Solution:**
To find the values of \( x \) and \( y \), we use the property that in a parallelogram, opposite sides are equal in length.
Therefore, we have:
1. \( ON = LM \)
2. \( NM = OL \)
From the first pair of equations:
\[ 7x - 5 = 6x + 3 \]
Solving for \( x \):
\[ 7x - 6x = 3 + 5 \]
\[ x = 8 \]
From the second pair of equations:
\[ x - 4 = 2y + 5 \]
Substitute \( x = 8 \):
\[ 8 - 4 = 2y + 5 \]
\[ 4 = 2y + 5 \]
Solving for \( y \):
\[ 4 - 5 = 2y \]
\[ -1 = 2y \]
\[ y = -\frac{1}{2} \]
Thus, the values are \( x = 8 \) and \( y = -\frac{1}{2} \).
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