If ON = 7x- 5, LM = 6x + 3, NM =x- 4, and OL = 2y + 5, find the values of x and y given that LMNOIS a parallelogram.

Elementary Geometry For College Students, 7e
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ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
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ChapterP: Preliminary Concepts
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**Mathematics Problem: Parallelogram Properties**

Given the equations:
\[ ON = 7x - 5 \]
\[ LM = 6x + 3 \]
\[ NM = x - 4 \]
\[ OL = 2y + 5 \]

**Problem:**
Find the values of \( x \) and \( y \) given that LMNO is a parallelogram.

**Solution:**
To find the values of \( x \) and \( y \), we use the property that in a parallelogram, opposite sides are equal in length.

Therefore, we have:
1. \( ON = LM \)
2. \( NM = OL \)

From the first pair of equations:
\[ 7x - 5 = 6x + 3 \]
Solving for \( x \):
\[ 7x - 6x = 3 + 5 \]
\[ x = 8 \]

From the second pair of equations:
\[ x - 4 = 2y + 5 \]
Substitute \( x = 8 \):
\[ 8 - 4 = 2y + 5 \]
\[ 4 = 2y + 5 \]
Solving for \( y \):
\[ 4 - 5 = 2y \]
\[ -1 = 2y \]
\[ y = -\frac{1}{2} \] 

Thus, the values are \( x = 8 \) and \( y = -\frac{1}{2} \).
Transcribed Image Text:**Mathematics Problem: Parallelogram Properties** Given the equations: \[ ON = 7x - 5 \] \[ LM = 6x + 3 \] \[ NM = x - 4 \] \[ OL = 2y + 5 \] **Problem:** Find the values of \( x \) and \( y \) given that LMNO is a parallelogram. **Solution:** To find the values of \( x \) and \( y \), we use the property that in a parallelogram, opposite sides are equal in length. Therefore, we have: 1. \( ON = LM \) 2. \( NM = OL \) From the first pair of equations: \[ 7x - 5 = 6x + 3 \] Solving for \( x \): \[ 7x - 6x = 3 + 5 \] \[ x = 8 \] From the second pair of equations: \[ x - 4 = 2y + 5 \] Substitute \( x = 8 \): \[ 8 - 4 = 2y + 5 \] \[ 4 = 2y + 5 \] Solving for \( y \): \[ 4 - 5 = 2y \] \[ -1 = 2y \] \[ y = -\frac{1}{2} \] Thus, the values are \( x = 8 \) and \( y = -\frac{1}{2} \).
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