If np≥5 and nq≥5, estimate P(fewer than 4) with n=13 and p=0.5 by using the normal distribution as an approximation to the binomial distribution; if np<5 or nq<5, then state that the normal approximation is not suitable
Q: Assume that a procedure yields a binomial distribution with n trials and the probability of success…
A: From the given information, n=1,500 and p=3/4 Binomial approximation to normal distribution…
Q: If np≥5 and nq≥5,estimate P(fewer than 7) with n=14 and p=0.5 by using the normal distribution as…
A:
Q: ssume that a procedure yields a binomial distribution with a trial repeated n=17 times. Find the…
A: given data, binomial distributionn=17x=6p=0.69q=1-0.69=0.31p(X=6)=?p(X=x)=nCx*px *qn-x ( binomial…
Q: If no is greater than or equal to 5, estimate P(fewer than 5) with n=14 and P=0.5 by using the…
A:
Q: if np greater than or equals 5 and nq greater than or equals 5, estimate Upper P left parenthesis…
A: Given: n = 14, p = 0.4, q = (1 – p) = 1 – 0.4 = 0.6 Following conditions must be satisfied to use…
Q: If np is greater than/or = to 5 and nq is greater than/or = 5, Estimate P(fewer than 7) with n=13…
A:
Q: Use the normal approximation to the binomial to find the probability for n=,10 p=0.5 and X≥8. Round…
A:
Q: If np>5 and nq <5, estimate P(fewer than 4) with n=14 and p= 0.5 by using the normal distribution as…
A: For a Binomial random variable X can be approximated to Normal, i.e…
Q: If np ≥ 5 and nq ≥ 5, estimate P(more than 8) with n=12 and p=0.7 by using the normal distribution…
A: From the provided information, Sample size (n) = 12 Probability (p) = 0.7
Q: If np 25 and nq 25, estimate P(fewer than 3) with n= 13 and p = 0.5 by using the normal distribution…
A: given data, n=13p=0.5we check the binomial distribution follows approximately normal ditribution…
Q: ≥5 and nq≥5, estimate P(fewer than 5) with n=13 and p=0.6 by using the normal distribution as an…
A: Given : n=13 and p=0.6
Q: If np > 5 and nq 2 5, estimate P(more than 9) withn = 13 and p = 0.6 by using the normal…
A: Given Data sample size,n= 13 probability of success,p= 0.6 probability of…
Q: If the requirements of np greater than or equals 5np≥5 and nq greater than or equals 5nq≥5 are both…
A:
Q: If np(is greater than or equal to)5, estimate P(fewer than 5) with n=13 and p=0.4 by using the…
A:
Q: If np 2 5 and ng 2 5, estimate P(fewer than 7) with n= 14 and p = 0.5 by using the normal…
A:
Q: Suppose that the random variable X has a normal distribution with mean 0 and variance 800. What is…
A: given the random variable X follows normal distribution mean(μ) =0variance =800we know the formula…
Q: If np≥5 and nq≥5, estimate P(fewer than 5) with n=13 and p=0.6 by using the normal distribution as…
A: np= 13×0.6=7.8>5 nq=13×0.4=5.2>5 We use normal approximation to calculate probability.
Q: If np 25 and nq25, estimate P(fewer than 7) with n= 14 and p%30.6 by using the normal distribution…
A:
Q: About 75% of all female heart transplant patients will survive for at least 3 years. Sixty female…
A: The population proportion, p=0.75 and sample proportion, p^=0.75. The sample of 60 female patients…
Q: suppose that 60% of all students currently enrolled at all California Community College campuses…
A: Part (e):The exact distribution of P is binomial distribution; here P ~ Bin (1,000, 0.6).Thus, the…
Q: If np≥5 and nq≥5,estimate P(fewer than 5) with n=14 and p=0.6by using the normal distribution as an…
A: Givenn =14, p=0.6 np=14*0.6=8.4nq=n(1-p)=14*(1-0.6)=14*0.4=5.6 np and nq values are both greater…
Q: If np≥5 and nq≥5, estimate P(at least 5) with n=13 and p=0.4 by using the normal distribution as an…
A:
Q: Suppose only 40% of all drivers in a certain state regularly wear seatbelts. A random sampleof 400…
A: Given,n=400p=0.40mean(μ)=npμ=400×0.40=160standard deviation(σ)=np(1-p)σ=400×0.40(1-0.40)σ=9.79796
Q: An unbalanced coin is tossed 10 times with a probability of heads p =0.73. Calculate P(x > 8) using…
A: Obtain the probability that the random variable X is greater than 8. The probability that the…
Q: If np≥5 and nq≥5 , estimate P(fewer than7) with n= 14 and p= .6 by using the normal distribution as…
A:
Q: If np 25 and nq25, estimate P(more than 5) with n= 12 and p= 0.3 by using the normal distribution as…
A: The requirements to check whether the normal distribution can be used to approximate the binomial…
Q: If you are given n=593n=593 and p=0.3p=0.3 for a binomial experiment, use the normal distribution to…
A: The random variable X follows normal distribution. We have to find the probability that X greater…
Q: Suppose X follows a binomial distribution with mean 8 and variance 1.6. (a) Find the values of n and…
A:
Q: If np ≥ 5 and nq ≥ 5, estimate P(fewer than 4) with n = 14 and p = 0.5 by using the normal…
A:
Q: Suppose that historically, 35% of applicants that are offered admittance to Texas Tech actually…
A: According to the given information, we have Sample size, n = 9300 Given that 35% of applicants that…
Q: The number of birth defects in a region is commonly modeled as having a binomial distribution, with…
A: p=sample size(n)=200
Q: If np greater than or equals 5 and nq greater than or equals 5 , estimate P(fewer than 4) with n=…
A:
Q: If np≥5 and np≥5, estimate P(fewer than 5) with n=14 and p=0.6 by using the normal distribution as…
A: Given, n = 14 and p = 0.6 q = 1 - p = 1 - 0.6 = 0.4 np = 14*0.6 = 8.4 which is greater than 5 nq =…
Q: If np > 5 and nq ≥ 5, estimate P(more than 5) with n = 12 and p = 0.6 by using the normal…
A: n=12p=0.6
Q: If np>5 and nq>5, estimate P(fewer than 8) with n = 14 and p = 0.6 by using the normal…
A: From the given information, Sample size (n) = 14 p=0.6 It has been given that, np < 5 or nq <5…
Q: given that the binomial distribution with 84 trials and a probability of success of 0.18 can be…
A: Given that, n= 84, p =0.18 The values of mean and standard deviation are,
Q: If np greater than or equals 5 and nq greater than or equals 5 , estimate P(at least 9) with n= 13…
A: Summary of this question It np is greater than or equal to 5 and nq is greater than or equals 5.
Q: If np≥5 and nq≥5,estimate P(fewer than 9) with n= 11 and p=0.6 by using the normal distribution as…
A: Solution
Step by step
Solved in 2 steps with 1 images
- If a binomial experiment has probability p success, then the probability of failure is ____________________. The probability of getting exactly r successes in n trials of this experiment is C(_________, _________)p (1p)Assume that a procedure yields a binomial distribution with �=1374 trials and the probability of success for one trial is �=52%.Find the mean for this binomial distribution.(Round answer to one decimal place.)�= Find the standard deviation for this distribution.(Round answer to two decimal places.)�= Use the range rule of thumb to find the minimum usual value μ–2σ and the maximum usual value μ+2σ.Enter answer as an interval using square-brackets only with whole numbers.usual values =The variable X denotes a binomial random variable with parameters n and p. Indicate which area under the approximate normal curve would be determined to approximate the given binomial probability. P(X=22) The area between the lower delimiting x-value, and the upper delimiting x-value, would be determined to approximate the binomial probability P(X= 22). (Use integers or decimals for any numbers in the expressions. Do not round.)
- Q2: Suppose the current measurements in a strip of wire are assumed to follow a normal distribution with a mean of 10 milliamperes and a variance of 4 (milliamperes)² 1- What is the probability that a measurement will exceed 13 milliamperes? 2- what is the probability that a current measurement is between 9 and 11 milliamperes?the time X that a lightbulb can last (life lenght) is a distribution with mean 1 year and standard deviation 0.5 years. suppose we have 100 such lightbulbs, what is the probability that the average life length of the lightbulks is greater than 1.02 years? what is theorem you are using here?of a defective bolt is 0.1, find the meqn, 8. If the probability and standard deviation for the distribution of defective bolts a total of 400, (assume Binomial distribution). in a
- Assume Binomial Distribution with n = 9 and p = .3. Please show your answers to 4 decimal places. P(X = 4) = P(X ≤ 4) = P(X < 4) = P(X > 4) = P(X ≥ 4) =Parts (a) and (b) are both related to normal distribution but are not directly connected to each other. Please complete both parts. Sketch two normal pdfs, both with u=-1, but one with (a) o=2 and the other with o =7. Label the curves. (b) Compute P(|Z| < 2.43). Assume that Z is a standard normal random variable. 2.Suppose X has a continuous uniform distribution over the interval -1,1. Determine the variance. Round your answers to 3 decimal places.
- Np>5 and nq>5, estimate P(at least 11) with n=13 and p = 0.6 by using the normal distributions as an approximation to the binomial distribution. if np<5 or nq<5 then state the normal approximation is not suitable. p (at least 11) =The variable X denotes a binomial random variable with parameters n and p. Indicate which area under the approximate normal curve would be determined to approximate the given binomial probability. P(X<10) The area between the lower delimiting x-value, and the upper delimiting x-value, would be determined to approximate the binomial probability P(X<10). (Use integers or decimals for any numbers in the expressions. Do not round.)Let x be a random variable that represents white blood cell count per cubic millimeter of whole blood. Assume that x has a distribution that is approximately normal with mean of 7500 and estimated standard deviation of 1750. A test result of x<3500 is an indication of leukopenia. This indicates bone marrow depression that may be the result of a viral infection. What is the probability that on a single test x<3500? Suppose that a doctor uses the average for two tests taken a week apart. What can we say about the probability distribution of ? What is the probability that <3500? Repeat part b with n = 3 tests taken a week apart. Compare your answers for parts a, b, and c. How did the probabilities change as n increased? If a person had <3500 based on three tests, what conclusion would you draw as a doctor or a nurse?