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← If np ≥ 5 and nq ≥ 5, estimate P(fewer than 3) with n = 13 and p = 0.5 by using the normal distribution as an approximation to the binomial distribution; if np <5 or nq <5, then state that the normal approximation is not suitable. Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. P(fewer than 3) = (Round to four decimal places as needed.) B. The normal approximation is not suitable.

← If np ≥ 5 and nq ≥ 5, estimate P(fewer than 3) with n = 13 and p = 0.5 by using the normal distribution as an approximation to the binomial distribution; if np <5 or nq <5, then state that the normal approximation is not suitable. Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. P(fewer than 3) = (Round to four decimal places as needed.) B. The normal approximation is not suitable.

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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how can u solve this using the ti 84 calculator please show me the step

← If np ≥ 5 and nq ≥ 5, estimate P(fewer than 3) with n = 13 and p = 0.5 by using the normal distribution as an approximation to the binomial distribution; if np < 5 or nq < 5, then state that the normal approximation is not suitable. Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. P(fewer than 3) = (Round to four decimal places as needed.) OB. The normal approximation is not suitable.
Transcribed Image Text:← If np ≥ 5 and nq ≥ 5, estimate P(fewer than 3) with n = 13 and p = 0.5 by using the normal distribution as an approximation to the binomial distribution; if np < 5 or nq < 5, then state that the normal approximation is not suitable. Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. P(fewer than 3) = (Round to four decimal places as needed.) OB. The normal approximation is not suitable.
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