If n=17n=17, ¯xx¯=35, and s=15s=15, construct a confidence interval at a 95% confidence level. Give your answers to 2 decimal place. < μμ <
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Q: If n=14, (x-bar)=43, and s=16, construct a confidence interval at a 98% confidence level. Assum the…
A: given data sample size (n) = 14sample mean ( x¯ ) = 43sample standard deviatio (s) =1698% ci for…
If n=17n=17, ¯xx¯=35, and s=15s=15, construct a confidence interval at a 95% confidence level. Give your answers to 2 decimal place.
< μμ <
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- Heights for teenage boys and girls were calculated. The mean height for the sample of 47 boys was 185 cm and the variance was 58. For the sample of 66 girls, the mean was 174 cm and the variance was 69. There is no reason to assume the variances would be equal. Estimate how much taller teenage boys are using a 87% confidence level. Express this in the (point estimate) ± (margin of error) format. Round answers to 2 decimal places. HIn each of Exercises, we have presented a confidence interval (CI) for the difference, µ1 - µ2, between two population means. Interpret each confidence interval. 99% CI is from -10 to 5.Find the z critical value associated with 85% confidence.
- Heights for teenage boys and girls were calculated. The mean height for the sample of 50 boys was 167 cm and the variance was 57. For the sample of 56 girls, the mean was 153 cm and the variance was 67. There is no reason to assume the variances would be equal. Estimate how much taller teenage boys are using a 99% confidence level. Express this in the (point estimate) ± (margin of error) format. Round answers to 2 decimal places. HYou measure 45 backpacks' weights, and find they have a mean weight of 37 ounces. Assume the population standard deviation is 3.5 ounces. Based on this, construct a 95% confidence interval for the true population mean backpack weight. Give your answers as decimals, to two places ± ouncesPlease solve by using R calculator or excel. Show all work.
- In each of Exercises, we have presented a confidence interval (CI) for the difference, µ1 - µ2, between two population means. Interpret each confidence interval. 99% CI is from -20 to 15.If n=24, (x-bar)=44, and s=18, construct a confidence interval at a 98% confidence level. Assume the data came from a normally distributed population. Give your answers to one decimal place.If n=27, (x-bar)=46, and s=19, construct a confidence interval at a 99% confidence level. Assume the data came from a normally distributed population. Give your answers to one decimal place. <μ<The distribution of scores on a standardized test is approximately Normal with standard deviation of σσ = 22. If a sample of 150 students had a mean score of x¯x¯ = 74.3, use this to find a 99% confidence interval for the mean score of all students on this test. We are 99% confident that the the mean score of students on this test was in the interval What is the margin of error for your confidence interval? Margin of error =If n=-22, (x-bar)=50, and s-6, construct a confidence interval at a 90% confidence level. Assume the data came from a normally distributed population. Give your answers to one decimal place.Round to three decimal places. For a confidence level of 99%, find the critical zSEE MORE QUESTIONSRecommended textbooks for youMATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons Inc
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