If n=10, The rejection region for testing Ho: p = 100 vs. Ha: P# 100 at the 0.01 level of significance is: Ot> 3.250 O I4 > 3.250 O> 1.645 O > 2.326
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- A geneticist was curious about the relationship between gender and dominant hand. They surveyed a random sample of 500 people. Here is a summary of the responses and the results from a chi-squared test: Chi-square test: Dominant hand vs. gender Men Women Right 207 227 Expected 208.32 225.68 Left 21 27 Expected 23.04 24.96 Ambidextrous 12 - Expected 8.64 9.36 X%3D2.876, DF 2, P-value 0.237 Assume that all conditions for inference were met. At the a = 0.05 significance level, what is the most appropriate conclusion to draw from this test? O This is convincing evidence that the distribution of dominant hand differs between the genders. O This isn't enough evidence to say that the distribution of dominant hand differs between the genders. O This is convincing evidence that dominant hand and gender are not independent. OThey lack evidence to say that dominant hand and gender are not independent. O Gender causes people to be more likely to be left- or right-handed.The data below are from a study comparing three different treatment conditions: Treatment 1 Treatment 2 Treatment 3 0 1 6 1 4 5 0 1 6 3 2 3 T = 4 T = 8 T = 20 SS = 6 SS = 6 SS = 6 N = 12 G = 32 ƩX2= 138 Conduct a single-factor independent-measures ANOVA to test the hypothesis that there are significant differences in the mean scores among the three treatment conditions. Use α = .01. a. The alternative hypothesis isTest the claim that the mean GPA of night students is different from the mean GPA of day students at the 0.01 significance level. The null and alternative hypothesis would be: Ho:µN – PD = 0 Ho:PN – pp = 0 Ho:UN – µD = 0 Ho:PN – PD = 0 HA:PN – µD 70 HA:PN – pp > 0 HA:µn – µD 0 The test is: two-tailed right-tailed left-tailed The sample consisted of 35 night students, with a sample mean GPA of 2.98 and a standard deviation of 0.02, and 80 day students, with a sample mean GPA of 3.03 and a standard deviation of 0.06. The test statistic is: (to 3 decimals) The positive critical value is: (to 3 decimals) The p-value is: (to 3 decimals)
- Assume significance level of a= 0.05: In a recent study of a random sample of 113 people, 92 reported dreaming in color. In the 1940’s, the proportion of people who reported dreaming in color was 29%. Is there evidence to show that the proportion of people who dream in color is different than the proportion in the 1940’s? What is the critical value for this hypothesis test? A) ±2.33 B) ±2.05 C) ±2.575 D) ±1.96 E) ±1.645Test the claim that the proportion of men who own cats is significantly different than the proportion of women who own cats at the 0.2 significance level.The null and alternative hypothesis would be: H0:μM=μFH0:μM=μFH1:μM<μFH1:μM<μF H0:pM=pFH0:pM=pFH1:pM<pFH1:pM<pF H0:pM=pFH0:pM=pFH1:pM≠pFH1:pM≠pF H0:pM=pFH0:pM=pFH1:pM>pFH1:pM>pF H0:μM=μFH0:μM=μFH1:μM>μFH1:μM>μF H0:μM=μFH0:μM=μFH1:μM≠μFH1:μM≠μF The test is: right-tailed left-tailed two-tailed Based on a sample of 40 men, 25% owned catsBased on a sample of 20 women, 30% owned catsThe test statistic is: (to 2 decimals)The p-value is: (to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesisTest the daim that the mean GPA of night students is smaller than the mean GPA of day students at the 0.05 significance level. The null and alternative hypothesis would be: Ho:PN = PD Ho:HN > Hp Ho:PN > PD Ho:HN = HD Ho:HN µp Ha:PN > PD The test is: right-tailed left-tailed two-tailed The sample consisted of 16 night students, with a sample mean GPA of 3.28 and a standard deviation of 0.02, and 14 day students, with a sample mean GPA of 3.3 and a standard deviation of 0.03. test statistic = [three decimal accuracy] p-value = [three decimal accuracy] Based on this we: O Fail to reject the null hypothesis O Reject the null hypothesis
- Women are recommended to consume 1790 calories per day. You suspect that the average calorie intake is smaller for women at your college. The data for the 15 women who participated in the study is shown below: 1959, 1908, 1789, 1544, 1805, 1656, 1899, 1811, 1686, 1688, 1687, 1943, 1612, 1789, 1467 Assuming that the distribution is normal, what can be concluded at the α = 0.05 level of significance? For this study, we should use The null and alternative hypotheses would be: H0: H1: The test statistic = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is α Based on this, we should the null hypothesis. Thus, the final conclusion is that ... The data suggest the population mean is not significantly less than 1790 at α = 0.05, so there is sufficient evidence to conclude that the population mean calorie intake for women at your college is equal to 1790. The data suggest the populaton…A new medication is being developed to treat severe nausea and vomiting among chemotherapy patients. The information below was generated from a small sample size (n = 11) and shows the number of times a chemotherapy patient vomited both before and after treatment due to the side effects of chemotherapy. Set up and interpret the results of a sign test at the alpha equals .05 level to determine if there is a difference in symptoms before and after treatment. Chemotherapy Patient Before Treatment After Treatment Difference Sign 1 9 3 2 12 5 3 14 7 4 9 4 5 8 2 6 11 3 7 15 7 8 12 8 9 7 8 10 9 5 11 8 7 A) We fail to reject H0, which states the median difference in the number of vomiting episodes in a day before and after treatment are equal because 1 is less or equal to critical value 1 for a sign test…Test the claim that the mean GPA of night students is smaller than the mean GPA of day students at the 0.025 significance level.The null and alternative hypothesis would be: H0:μN=μDH0:μN=μDH1:μN≠μDH1:μN≠μD H0:pN≤pDH0:pN≤pDH1:pN>pDH1:pN>pD H0:μN≤μDH0:μN≤μDH1:μN>μDH1:μN>μD H0:pN≥pDH0:pN≥pDH1:pN<pDH1:pN<pD H0:pN=pDH0:pN=pDH1:pN≠pDH1:pN≠pD H0:μN≥μDH0:μN≥μDH1:μN<μDH1:μN<μD The test is: left-tailed two-tailed right-tailed The sample consisted of 35 night students, with a sample mean GPA of 3.34 and a standard deviation of 0.06, and 35 day students, with a sample mean GPA of 3.36 and a standard deviation of 0.03.The test statistic is: _____ (to 2 decimals)The p-value is: ____ (to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesis
- Test the daim that the proportion of men who own cats is significan tly different than the proportion of women who own cats at the 0.02 significance level. The null and alternative hypothesis would be: Ho:PM = PF Ho:HM PF Ho:PM µp H1:µM PF H1:µM + HF The test is left-tailed two-tailed right-tailed Based on a sample of 80 men, 40% owned cats Based on a sample of 20 women, 50% owned cats positive Critical Value = [three decimal accuracy] Test Statistic = [three decimal accuracy] Based on this we: O Reject the null hypothesis O Fail to reject the null hypothesisYou wish to test the following claim (Ha) at a significance level of a = Ho: P₁ = P2 Ha: P₁ P2 You obtain a sample from the first population with 120 successes and 403 failures. You obtain a sample from the second population with 39 successes and 278 failures. The test statistic is... in the critical region O not in the critical region critical value = ± test statistic = This test statistic leads to a decision to... reject the null hypothesis fail to reject the null hypothesis = 0.005. O There is not sufficient evidence to support second population proportion. [three decimal accuracy] [three decimal accuracy] As such, the final conclusion is that... There is sufficient evidence to support that the first population proportion is not equal to the second population proportion. first population proportion not equal to theA study is made of residents in Phoenix and its suburbs concerning the proportion of residents who subscribe to Sporting News. A random sample of n, = 86 urban residents showed that r, = 14 subscribed, and a random sample of n, = 97 suburban residents showed that r = 20 subscribed. Does this indicate that a higher proportion of suburban residents subscribe to Sporting News? Use a 5% level of significance. What are we testing in this problem? O difference of means O difference of proportions O paired difference O single mean O single proportion (a) What is the level of significance? State the null and alternate hypotheses. O Ho: P1 P2 O Ho: P1 = P2i H1: P1 0.250 O 0.125 < P-value < 0.250 O 0.050 < P-value < 0.125 O 0.025 < P-value < 0.050 O 0.005 < P-value < 0.025 O P-value < 0.005