If n = 20, = 43, and s = at a 90% confidence level. Assume the data came from a 4, construct a confidence interval normally distributed population. Give your answers to three decimal places.
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A: Given: x¯=31n=32s=1495% confidence level
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Q: If n=30, ¯xx¯(x-bar)=43, and s=16, construct a confidence interval at a 98% confidence level. Assume…
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A: The sample size is 1060 and number of success is 169.
Q: If n = 28, ¯xx¯ = 49, and s = 19, construct a confidence interval at a 90% confidence level. Assume…
A: Given information- Sample size, n = 28 Sample mean, x-bar = 49 Sample standard deviation, s = 19…
Q: If n = 16, 7 = 43, and s = 17, construct a confidence interval at a 98% confidence level. Assume the…
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Q: If n=22, ¯xx¯(x-bar)=46, and s=8, construct a confidence interval at a 98% confidence level. Assume…
A: It is given that mean and standard deviation are 46 and 8, respectively.
Q: If n = 25, ¯x = 50, and s = 19, construct a confidence interval at a 99% confidence level. Assume…
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Q: If n-28, 2(x-bar)-38, and s-13, construct a confidence interval at a 98% confidence level. Assume…
A: Given : Sample Size, n = 28 Sample Mean, x̄ = 38 sample standard…
Q: If n=27, (x-bar)=34, and s=3, find the margin of error at a 90% confidence leve Give your answer to…
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Q: If n-19, ž(x-bar)-43, and s-8, construct a confidence interval at a 90% confidence level. Assume the…
A: Given: n = 19, x¯ = 43, s = 8 Confidence level = 90%
Q: If n = 15, ¯x = 50, and s = 9, construct a confidence interval at a 90% confidence level. Assume the…
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Q: Use the given data to construct a confidence interval for the population proportion p of the…
A: It is given that sample size (n) is 70 and x is 50.
Q: one with a 95% confidence level and the other with a 99.7% confidence level. Which interval is…
A: Confidence interval is probability, which refers that population parameter will fall within set of…
Q: When 290 college students are randomly surveyed, it is found that 120 own a car. Find a 99%…
A: Given that, x=120,n=290 The sample proportion is, Critical values: By using the standard normal…
Q: Express the confidence interval (77.4 % , 89.2 % ) in the form of p ± ME.
A: GivenConfidence Interval(77.4% , 89.2%)
Q: If n=13, ¯x(x-bar)=44, and s=3, construct a confidence interval at a 99% confidence level. Assume…
A: Here, n is 13, x-bar is 44, and s is 3. Critical value: Using Excel formula…
Q: 13, ¤(x-bar)=39, and s=16, construct a confidence interval at a 90% confidence level. Assume the…
A: From the given information, n=13 x-bar=39 s=16 Confidence level=90% Significance level=10%…
Q: Kindly tell what is confidence interval in stats thanks.
A: An essential idea in statistics is a confidence interval (CI), which provides a range that, with a…
Q: If n=15, ¯xx¯(x-bar)=40, and s=9, construct a confidence interval at a 98% confidence level. Assume…
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Q: If n = 41, ã=30, and s = 6, construct a confidence interval at a 80% confidence level.
A: It is given that Sample size n = 41 Sample mean = 30 Sample SD s = 6 The critical value of t at df =…
Q: If n = 15, the sample mean = 150, SD = 10, what is the confidence interval (using 99% confidence…
A: Given data,n=15x=150σ=10z-value at 99% confidence is Zc=2.576
Q: f n=200 and X=80, construct a 99% confidence interval estimate for the population proportion.
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Q: If n=15, ¯xx¯(x-bar)=33, and s=19, construct a confidence interval at a 80% confidence level. Assume…
A: Given' : sample mean xbar=33 sample size n=15 sample standard deviations s=14 then to find 80%…
Q: If n=14, (x-bar)=46, and s=18, construct a confidence interval at a 80% confidence level. Assume the…
A: Since population standard deviation is unknown, Use t-distribution to find t-critical value. Find…
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Q: Of the 1,000 people, 550 people used company s's smartphone and 460 people used company a's…
A: Given: n= 1000 ,x= 550.0 At 95.0 % confidence level , z score= 1.96 Need to find confidence…
Q: f n=19, sample mean=50, and s =8, construct a confidence interval at a 99% confidence level. Assume…
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Q: Construct the 99.8% confidence interval for the difference P1 - P2 when x, = 23, n, = 53, x2 = 15,…
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Q: If n = 81, -45, and s to one decimal place. = 8, construct a confidence interval at a 90% confidence…
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Q: All else constant, a 90% confidence interval for u will be wider than a 95% confidence inter True…
A: The confidence levels are 0.90 and 0.95.
Q: Construct a 90% confidence interval for the mean when x̅=50 and there are 31 observations. Suppose…
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Q: If a 90%, a 95% and a 99% confidence interval are foung for a population mean, describe how the 3…
A: Population mean CI for known population standard deviation is, CI=x¯±Zσnwhere,σ=population standard…
Q: now find the 99% confidence interval given the same information, x=13
A: The given regression equation is y^=7+15x se=10.14X__=7n=22∑Xi-X__2=200
Q: A recent survey conducted in a nearby town showed that 791 out of 1,495 people do most their holiday…
A: Here, the sample proportion is =7911495=0.5291 Now, for 90% confidence z=1.645
Q: Out of 500 people sampled, 145 received flu vaccinations this year. Based on this, construct a 90%…
A: We have given that Sample size n=500 , favorable cases x=145 90% confidence interval Sample…
Q: If n = 11,(x -bar)= 31, and s = 19, construct a confidence interval at a 99% confidence level.…
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Q: Translate the statement into a confidence interval. Approximate the level of confidence. In a survey…
A: The confidence interval proportion is obtained below: From the given information, the proportion…
Q: 15, ¯xx¯(x-bar)=39, and s=11, construct a confidence interval at a 95% confidence level. Assume the…
A: Sample size (n) =15 Sample mean (x¯)=39 Sample standard deviation (s)=11 Confidence level (C)=95%…
Q: In one city, 27.8% of the 9000 students surveyed said they eat at the school cafeteria. Find the 95%…
A: To find the 95% confidence interval for the proportion of students who said they eat at the school…
Q: In a survey conducted to 415 people it was found that they had walked 5000 meters on average for the…
A: Sample size (n) = 415Sample mean (x̅) = 5000Standard deviations (s) = 900 Confidence level (c) =…
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- If n = 20, the sample mean = 250, SD = 15, SEM = 3.354, what is the confidence interval (using 95% confidence level). What percent confidence do you have that the population mean is between what two valuesA Gallup survey of 2324 adults (at least 18 years old) in the U.S. found that 417 of them have donated blood in the past two years. Construct a 90% confidence interval for the population proportion of adults in the U.S. who have donated blood in the past two years. Round your answer to three decimal places. Use Z = 1.645. Use the unrounded values in Excel to find the answers to #2, #3 and #4 1. Find the sample proportion of adults in the U.S. who have donated blood in the past two years. Round your answer to three decimal places. 2. The standard error for sample proportion has a value of V 3. The margin of error has a value of 4. Construct the 90% confidence interval for adults who have donated blood in the past tTina catches a 14-pound bass. She does not know the population mean or standard deviation. So she takes a sample of five friends and they say the last bass they caught was 9, 12, 13, 10, and 10 pounds. Find the t and calculate a 95% (α = .05) confidence interval.
- Suppose you compute a 93% confidence interval. What will happen to the confidence interval if you decrease the confidence level to 91%?If n=20, ¯xx¯(x-bar)=43, and s=10, construct a confidence interval at a 98% confidence level. Assume the data came from a normally distributed population.Give your answers to one decimal place.If n=16, x¯(x-bar)=48, and s=7, construct a confidence interval at a 98% confidence level. Assume the data came from a normally distributed population.Give your answers to one decimal place.
- Find z* for a confidence level of 83%. Give your answer to 3 decimal places.From a sample of 500 Pepperdine students, 205 said they commuted to school. Find the 95% confidence interval using 2 decimal places for the proportion of Pepperdine students who commute. If you use a calculator, indicate the function used and the parameters you entered for the function.