If (n + 1)(n + 2)an+1x" - nan-1x" = 0, n=1 show that for k = 1, 2, 3, ..., we have 1.3.5... (2k - 1) ao, 2k+1 k! a1. (2k + 2)! a2k a2k+1 = (2k + 1)!

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