If n = 180 and p = 0.8, construct a 95% confidence interval about the population proportion. Round youranswers to three decimal places.Preliminary:a. Is it safe to assume that n < 0.05 of all subjects in the population?O NoO Yesb. Verify np (1 – p) > 10. Round your answer to one decimal place.пр(1 — р)Confidence Interval: What is the 95% confidence interval to estimate the population proportion? Roundyour answer to three decimal places.

Given that : Sample size (n) = 180 P = 0.8 Confidence interval = 95% By using proportion confidence…

Answered: If n = 180 and p = 0.8, construct a 95%…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Calculate the margin of error of a confidence interval for the difference between two population means using the given information. Round your answer to six decimal places. σ1=13.77, n1=87, σ2=10.46, n2=96n, c=0.95
Solve the last part
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About 25 randomly selected people were asked how long they slept at night. The mean time was 6 hours, and the standard deviation was 1 hour. Calculate the 98% confidence interval of the mean time by assuming that the variable is normally distributed. Provide only the value required below. Express your answer in 3 decimal places. a. tą (positive value only):
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In a survey of 2025 adults in a recent year, 711 made a New Year's resolution to eat healthier. Construct 90% and 95% confidence intervals for the population proportion. Interpret the results and compare the widths of the confidence intervals. The 90% confidence interval for the population proportion p is (.334 , .369 (Round to three decimal places as needed.) The 95% confidence interval for the population proportion p is ( ) (Round to three decimal places as needed.)
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