All the necessary values have been found to find the 95% confidence interval. We have x = 832, Za/2 = 1.960, o = 150, and n = 100. Find the lower bound of the confidence interval, rounding the result to the nearest integer. X-E = X-²a/2 = 832 - x+E=x+Za/2 Find the upper bound of the confidence interval, rounding the result to the nearest integer. of 0 = 832 + /100 O √n 150 V100 Therefore, rounded to the nearest integer, a 95% confidence interval for the population mean examination score is from a lower bound to an upper bound of
All the necessary values have been found to find the 95% confidence interval. We have x = 832, Za/2 = 1.960, o = 150, and n = 100. Find the lower bound of the confidence interval, rounding the result to the nearest integer. X-E = X-²a/2 = 832 - x+E=x+Za/2 Find the upper bound of the confidence interval, rounding the result to the nearest integer. of 0 = 832 + /100 O √n 150 V100 Therefore, rounded to the nearest integer, a 95% confidence interval for the population mean examination score is from a lower bound to an upper bound of
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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![Step 3
All the necessary values have been found to find the 95% confidence interval. We have x = 832, Za/2 = 1.960, o = 150, and n = 100.
Find the lower bound of the confidence interval, rounding the result to the nearest integer.
O
X-E = X-Za
²a/2
= 832-
X+ E = x + z
of
Find the upper bound of the confidence interval, rounding the result to the nearest integer.
a/2
0
√n
= 832 +
150
100
O
150
/100
Therefore, rounded to the nearest integer, a 95% confidence interval for the population mean examination score is from a lower bound
to an upper bound of
X
DELL
74°F Sunny
Ō
(4¹)
12:05 PM
4/13/2023](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fff516d2f-71a8-4a20-b0ff-ba0b765c8c1a%2F43cd2a8e-f37e-42e3-bdc2-7c2175c96710%2Fgc86acq_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Step 3
All the necessary values have been found to find the 95% confidence interval. We have x = 832, Za/2 = 1.960, o = 150, and n = 100.
Find the lower bound of the confidence interval, rounding the result to the nearest integer.
O
X-E = X-Za
²a/2
= 832-
X+ E = x + z
of
Find the upper bound of the confidence interval, rounding the result to the nearest integer.
a/2
0
√n
= 832 +
150
100
O
150
/100
Therefore, rounded to the nearest integer, a 95% confidence interval for the population mean examination score is from a lower bound
to an upper bound of
X
DELL
74°F Sunny
Ō
(4¹)
12:05 PM
4/13/2023
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