If lengths of rail track are laid down in cold weather, they may deform as they expand when the weather becomes warmer. Therefore, when rails are laid in cold weather they are stretched and fixed into place while still stretched. This is called pre-straining. The following data is typical for a length of steel rail: Young modulus of steel = 2.0 x 1011 Pa Cross sectional area of a length of rail = 7.5 x 10-3 m2 2.5 x 10-5 for each kelvin Amount of pre-strain = rise in temperature the rail is expected to experience. A steel rail is laid when the temperature is 8 °C and the engineer decides to use a pre-strain of 3.0 x 10-4. (a) Calculate the tensile force required to produce the pre-strain in the rail required by the engineer. (b) Calculate the elastic strain energy stored in a rail of unstressed length 45 m when pre-strained as in part (a) (c) Calculate the temperature at which the steel rail becomes unstressed.

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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QUESTION 4.
If lengths of rail track are laid down in cold weather, they may deform as
they expand when the weather becomes warmer. Therefore, when rails
are laid in cold weather they are stretched and fixed into place while still
stretched. This is called pre-straining.
The following data is typical for a length of steel rail:
Young modulus of steel =
2.0 x 101 Pa
Cross sectional area of a length of rail =
7.5 x 10-3 m2
Amount of pre-strain =
rise in temperature the rail is expected to experience.
2.5 x 10-5 for each kelvin
A steel rail is laid when the temperature is 8 °C and the engineer
decides to use a pre-strain of 3.0 x 104.
(a) Calculate the tensile force required to produce the pre-strain in
the rail required by the engineer.
(b) Calculate the elastic strain energy stored in a rail of unstressed
length 45 m when pre-strained as in part (a)
(c)
Calculate the temperature at which the steel rail becomes
unstressed.
(d) Explain why the engineer does not use the highest observed
temperature at the location of the railway track to determine the
amount of pre-strain to use.
Transcribed Image Text:QUESTION 4. If lengths of rail track are laid down in cold weather, they may deform as they expand when the weather becomes warmer. Therefore, when rails are laid in cold weather they are stretched and fixed into place while still stretched. This is called pre-straining. The following data is typical for a length of steel rail: Young modulus of steel = 2.0 x 101 Pa Cross sectional area of a length of rail = 7.5 x 10-3 m2 Amount of pre-strain = rise in temperature the rail is expected to experience. 2.5 x 10-5 for each kelvin A steel rail is laid when the temperature is 8 °C and the engineer decides to use a pre-strain of 3.0 x 104. (a) Calculate the tensile force required to produce the pre-strain in the rail required by the engineer. (b) Calculate the elastic strain energy stored in a rail of unstressed length 45 m when pre-strained as in part (a) (c) Calculate the temperature at which the steel rail becomes unstressed. (d) Explain why the engineer does not use the highest observed temperature at the location of the railway track to determine the amount of pre-strain to use.
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