f in a tensile loading application, the factor of safety for one member is set as FS = 2.2 based on the material's tensile (failure) strength as = 614 MPa, then the load member's allowable stress in this application will be: = _______ MPa. Calculate your answer to 1 decimal place. If in a tensile loading application, the factor of safety for one member is set as FS = 2.2 based on the material’s tensile (failure) strength as $ \sigma_{(fail)} = 614 \, \text{MPa} $, then the load member's allowable stress in this application will be: $ \sigma_{(allow)} = \, \_\_\_\_\_ \, \text{MPa} $. Calculate your answer to 1 decimal place.

Answered: If in a tensile loading application,…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

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f in a tensile loading application, the factor of safety for one member is set as FS = 2.2 based on the material's tensile (failure) strength as = 614 MPa, then the load member's allowable stress in this application will be: = _______ MPa. Calculate your answer to 1 decimal place.

If in a tensile loading application, the factor of safety for one member is set as FS = 2.2 based on the material’s tensile (failure) strength as $ \sigma_{(fail)} = 614 \, \text{MPa} $, then the load member's allowable stress in this application will be: $ \sigma_{(allow)} = \, \_\_\_\_\_ \, \text{MPa} $. Calculate your answer to 1 decimal place.

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$Given : Factor of safety, FS = 2.2 Tensile (failure) strength, σ_{(fail)} = 614 MPa Find : The load member' s allowable stress, σ_{(allow)}$

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