If I have the following variablesThe first variable (risk) and the value of the VAR was 0.002748, and the standard deviation value and thevalue of its standard deviation 0.0476951second variable(Chi^2) The value of the var was equal to 214.45and the third variable (prop) The value of its VAR is 0.000Accurately interpret these results for one-third variables.

It seems like you provided information about three different statistical measures for three…

Answered: If I have the following variables The…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Similar questions

If I have a mean of 98.7 and a standard deviation of 0.07 how do I find the IQR. I know I have to find the z scores and use Q1and Q3. But finding the Q's is uncleear. I asked a similar question but didn't understand the answer. They used 0.25 in solution saying I had to find a z-score from excel something (0.25) I have no idea what that means. Really lost on locating the z score and finding the Q's
I'm a bit confused about how to solve this (any help is appreciated)
I wanted to test if the mean Exam 3 score in this course was different than the mean Exam 2 score. To conduct this test I used the 30 students in my course last semester as my sample. I first calculated the difference in scores between Exam 2 and Exam 3 ("Exam 2 score - Exam 3 score"). The sample mean of these differences is 2.0 and the sample standard deviation of the differences is 3.0. What is your decision for this test? Group of answer choices 1. Reject the null hypothesis 2. Retain the null hypothesis
what was the right answer for the wrong ones
A researcher collected BMI (Body Mass Index) of 50 students in an Engineering school. He found the mean BMI was much smaller than the median BMI. The reason for this might be Select the correct response: Several students had much larger BMI scores than the rest Several students had much smaller BMI scores than the other students All the students had smaller BMI scores, compared to national average The researcher made some measurement errors
Why does Value of Standard Deviation Cannot Be Negative?
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for data set of the pulse rates for a sample of adult females the lowest pulse rate is 36 bpm the mean of the list of pulse rate is X bar equals 72 bpm and their standard deviation is 12.9 bpm. what is the difference between the pulse rate of 36 bpm and the meatballs rid of the females how many celebrations is that the difference found in part a convert the pulse rate of 36 bpm to a z score if we consider pulse rates that convert to a Z score between -2 and 2 to be neither significantly lower significantly high is the pulse rate of 36bpm significant
Suppose X is normal with mean=15 and standard-deviation=2. Find the X value so that 4% of all values are below this X value. Show how you use z table, show the graphics to present the answer in a good way.

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