If ƒ(x) = x² + x − 2, find3f(−2a). Show your work using the Equation Editor Tool. Paragraph v B I U A/ > ▶II O + ...

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter9: Quadratic Functions And Equations
Section: Chapter Questions
Problem 9SGR
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### Problem Statement

If \( f(x) = x^2 + x - 2 \), find \( 3f(-2a) \). Show your work using the Equation Editor Tool.

### Steps to Solve the Problem

First, substitute \(-2a\) for \(x\) in the function \(f(x)\):

\[ f(-2a) = (-2a)^2 + (-2a) - 2 \]

Next, simplify the expression:

\[ f(-2a) = 4a^2 - 2a - 2 \]

Now, multiply the function \(f(-2a)\) by 3:

\[ 3f(-2a) = 3 \cdot (4a^2 - 2a - 2) \]
\[ 3f(-2a) = 12a^2 - 6a - 6 \]

So, the final answer is:

\[ 3f(-2a) = 12a^2 - 6a - 6 \]
Transcribed Image Text:### Problem Statement If \( f(x) = x^2 + x - 2 \), find \( 3f(-2a) \). Show your work using the Equation Editor Tool. ### Steps to Solve the Problem First, substitute \(-2a\) for \(x\) in the function \(f(x)\): \[ f(-2a) = (-2a)^2 + (-2a) - 2 \] Next, simplify the expression: \[ f(-2a) = 4a^2 - 2a - 2 \] Now, multiply the function \(f(-2a)\) by 3: \[ 3f(-2a) = 3 \cdot (4a^2 - 2a - 2) \] \[ 3f(-2a) = 12a^2 - 6a - 6 \] So, the final answer is: \[ 3f(-2a) = 12a^2 - 6a - 6 \]
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