If force of 10//3 N is applied horizontally on a block of mass 1 kg as shown in the figure, the frictional force acting on the block is u=0.5 FH = 10/V3 ui 30°
If force of 10//3 N is applied horizontally on a block of mass 1 kg as shown in the figure, the frictional force acting on the block is u=0.5 FH = 10/V3 ui 30°
University Physics Volume 1
18th Edition
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:William Moebs, Samuel J. Ling, Jeff Sanny
Chapter12: Static Equilibrium And Elasticity
Section: Chapter Questions
Problem 37P: To get up on the roof, a person (mass 70.0 kg) places 6.00-m aluminum ladder (mass 10.0 kg) against...
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![If force of 10/3 N is applied
horizontally on a block of mass 1 kg
as shown in the figure, the frictional
force acting on the block is
H=0.5
FH = 10/V3
m
%3D
30°](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4fd7ed89-1395-4b5d-9f12-5a79dbd6a6ad%2Ff8291964-ad44-45c1-95e2-2df2240cbbdf%2F1648ngl_processed.jpeg&w=3840&q=75)
Transcribed Image Text:If force of 10/3 N is applied
horizontally on a block of mass 1 kg
as shown in the figure, the frictional
force acting on the block is
H=0.5
FH = 10/V3
m
%3D
30°
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