1)A battery with 1.50 n of internal resistance is connected to two resistors of resistances R1 = 30.0 0 and R2 = 130.0 n, wired in parallel. The current through R1 is 11 = 0.34 A. ン a) Determine the current 12 through R2. 60.0 2 Ta 180 b) How large is the current through the battery? V0.24 A c) How large is the terminal voltage of the battery? U 00
1)A battery with 1.50 n of internal resistance is connected to two resistors of resistances R1 = 30.0 0 and R2 = 130.0 n, wired in parallel. The current through R1 is 11 = 0.34 A. ン a) Determine the current 12 through R2. 60.0 2 Ta 180 b) How large is the current through the battery? V0.24 A c) How large is the terminal voltage of the battery? U 00
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Chapter1: Units, Trigonometry. And Vectors
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Transcribed Image Text:1)A battery with 1.50 Q of internal resistance is connected to two resistors of resistances R1 = 30.O
and R2 = 130.0 0, wired in parallel. The current through R1 is 11 0.34 A.
a) Determine the current 12 through R2.
60.0 2
180. 2l
b) How large is the current through the battery?
c) How large is the terminal voltage of the battery?
V0.24 A
E, 9V
R, 10-2
4.
2)Use Kirchhoff's Laws to determine the value of R2, shown in the
Figure , so that the current 13 through R3, equals twice the
current /2 through R2. The values of other circuit elements are
e1 = 9V, £2 = 12V, R1 = 100, and R3 = 200
.9
R2
12V
R2=
.75A
B
i, =
A
1052
T6.52 D
12-9=3V
3U
x2/R,2r
2
3.
ー,ろ4
,75A
%3D
3)In the circuit shown in the Figure, the resistors R1 = 500,
R = 30 2
R2 = 300, and R3 = 200 are connected to a power supply
with & = 120V.
R, = 20n
A) Replace the resistors R1, R2, and R3 with a single
equivalent resistor, R.
R=
30
1.672
it
R, =50SL
3.
120V
20
B) Determine the total current / through the circuit,
then find the currents /2 and /3 through resistors R2
and R3.
R3=R2=
34
120V
Iz=Ig=
=10A
%3D
122
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