If for the pipe carrying water in a building, h = 146.51 meters, v1 = 3.842 m/s, and the cross-sectional area at 1 is twice that at 2, what must P1 be (in KPa), in order that P2 = 105.6 KPa?

University Physics Volume 1
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Chapter14: Fluid Mechanics
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Problem 113AP: The flow of blood through a 2.00106 m -radius capillary is 3.80109cm3/s . (a) What is the speed of...
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If for the pipe carrying water in a building, h
= 146.51 meters, v1
=
3.842 m/s, and the cross-sectional
area at 1 is twice that at 2, what must P1 be (in KPa), in order that P2
=
105.6 KPa?
Transcribed Image Text:If for the pipe carrying water in a building, h = 146.51 meters, v1 = 3.842 m/s, and the cross-sectional area at 1 is twice that at 2, what must P1 be (in KPa), in order that P2 = 105.6 KPa?
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