Flow rate is expressed as gas velocity in cm/s. The gas is flowing through an open tubular column with an inner diameter of 0.25 mm. What volume flow rate (mL/min) corresponds to a gas velocity of 50 cm/s? (The volume of a cylinder is pr2 3 length, where r is the radius.)
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Flow rate is expressed as gas velocity in cm/s. The gas is flowing through an open tubular column with an inner diameter of 0.25 mm. What volume flow rate (mL/min) corresponds to a gas velocity of 50 cm/s? (The volume of a cylinder is pr2 3 length, where r is the radius.)
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- The gas law for an ideal gas at absolute temperature T (in kelvins), pressure P (in atmospheres), and volume V (in liters) is PV = nRT, where n is the number of moles of the gas and R = 0.0821 is the gas constant. Suppose that, at a certain instant, P = 9.0 atm and is increasing at a rate of 0.15 atm/min and V = 13 L and is decreasing at a rate of 0.17 L/min. Find the rate of change of T with respect to time at that instant if n = 10 mol. (Round your answer to four decimal places.) K/min dT_ dtAir flows at 210 m/s through the pipe. The temperature is 400 K and the absolute stagnation pressure is 280 kPa. Assume isentropic flow. For air R = 286.9 J/[kg - K] and k=1.40. (Figure 1) Figure 0.3 mWhat is the pressure of the gas in the cylinder, in kPa (kiloPascal)? h = 0.620 m, Pmercury = 13,600 kg/m3, 1.0 atm = 1.00 x 105 Pa = 100 kPa, and g = 10.0 m/s?. Your answer needs to have 3 significant figures, including the negative sign in your answer if needed. Do not include the positive sign if the answer is positive. No unit is needed in your answer, it is already given in the question statement. Mercury. p = 13,600 kg/m² Pen
- The vapor pressure of mercury at 25°C is 0.00243 atm. Calculate the vapor pressure in kPa. Round answer to 3 significant digits.A rectangular block of copper alloy has a mass of 1896 g. The dimensions of the block are 8.4 cm by 5.5 cm by 4.6 cm. From this data, what is the density of copper? 9386 kg/m³ O 0.112 kg/m³ 402938 kg/m3 2650 kg/m3 8922 kg/m³ 5498 kg/m³The gas law for an ideal gas at absolute temperature T (in kelvins), pressure P (in atmospheres), and volume V (in liters) is PV = nRT, where n is the number of moles of the gas and R = 0.0821 is the gas constant. Suppose that, at a certain instant, P = 9.0 atm and is increasing at a rate of 0.15 atm/min and V = 13 L and is decreasing at a rate of 0.17 L/min. Find the rate of change of T with respect to time at that instant if n = 10 mol. (Round your answer to four decimal places.) dT=0.512 dt X K/min