If E (X) = 1 and Var (X) = 4 then E (X² + 2X – 1) = :- 1)

Q: There are 4 treatments, so we have k4 and k-1- A total of 18 men undenvent Treatment 1 giving n, -…

A: The number of treatments k is 4.

Q: 2. Given g(x) = (3x+ 2)(x- 2), determine each value. a) g(0) b) g(-1) c) g(1/2)

A: The given function,   g(x)=3x+2x-2

Q: Let f(x) = 3x + 4 and g(x) = -2x – 3. What is (f o g)(x)?

A: We have to solve

Q: If f(x) = (x − 2) 5(2x+1) 6, then what is f"(0) ?

A:

Q: Explain Bayes theorem with examples and applications.

A: BAYES' THEOREM It is a concept used to determine the conditional probability of events. Consider two…

Q: Suppose that f(x) = (x - 4)*.

A: At the point of inflection, f''(x)=0.

Q: Let f(x) =x²-x -5 and gx)= -8x+4. Find g(3) and f(g(3)). %3D 9(3) = f(g(3)) = %3D %3D

A:

Q: find h(1) = 1 + h(-1), h(2), h(+), h(x – 1), h

A:

Q: If E[X] = −3 and Var(X) = 5, then E[(5 + 6X)²] = and Var(3 + 5X) =

A:

Q: If P(x)=x2+x+3 and Q(x)=5x2−1​, find Q (1/4)

A:

Q: erify the result C(X"X) = C(X") for %3D x-(; ) X = -1 0 %3D

A: We have to solve given problems:

Q: + 1) =-2fn what

A: Function: f(1)=160   f(n + 1) =-2f(n) If we put n=1 f(1+1)=-2f(1) f(2)=-2.160 f(2)=-320

Q: If f(x) = x3 + 1, then give the following

A: Consider the function: fx=x3+1

Q: Find the indicated outputs for f(x) = 2x² - - 2x.

A:

Q: if h(x)=x2-6, find h-1(x)

A: To find the inverse of the function, use the below steps. Replace h(x) by y, so we get y = x2 - 6

Q: Differentiate. f(x) = (x 2 - 2x + 4)ex O ex(x² + 2) O ex(x² + 4x + 2) 3 +x+4 O ex(2x - 2)

A: Given the function fx=x2-2x+4ex

Q: If f(x) = 5x + 7 and g(x) = -2x – 4 Find g(f(x)) = [ ? ]x + O

A:

Q: If f(x).= x³+3x k is divided by (x +1) and the remainder is 12, then - k = -8. True False

A: Given :fx=x3+3x-k*Remainder theorem; - If a polynomial f(x) is divided by x-a then the remainder is…

Q: = 4, fi(5) = -1, g(5) 2, and g (5) 25. If f(5) 2f(a) 3g(x) 3, find hi(5) if h(a) =

A: Differentiate the given function on both the sides with respect to x to get an expression for h’(x);

Q: If h(x) = (4x – 7)/5   then h-1(x) =

A: