If both the mass of a simple pendulum and its length are doubled, the period will increase by a factor of 4. increase by a factor of 1/√2. be unchanged. increase by a factor of 2. O increase by a factor of V √2
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- A simple pendulum has a length of 1.3 meters. What is its period of oscillation? Use g = 9.8 m/s/s Give your answer in seconds to 1 decimal place.A given mass and spring system oscillates with an amplitude A and a period T. When the amplitude is doubled, when then happens to the period? Be specific 4x, 2x, the same, ½ x, ¼ x, etc ExplainWhat is the length, in meters, of a simple pendulum if it has a period of 4.92 s? Assume that the pendulum is on a planet where the acceleration due to gravity is 13.05 m/s2.
- 3. A simple harmonic oscillator consists of a block attached to a spring with k = 200 N/m. The block slides on a frictionless surface, with equilibrium point x = 0 and amplitude 0.20 m. A graph of the block's velocity v as a function of time t is shown. The horizontal scale is set by t, = 0.20 s.What v (m/s) t (s) are -2n the period of the SHM the block's mass а. b. it's displacement at t = 0 it's acceleration at t = 0.10 s, and it's maximum kinetic energy? С. d. е.Problem 9: An ideal pendulum of length L=1.1 m supports a mass of m =0.5 kg. Initially the pendulum is lifted such that it makes an angle of 0 = 26 degrees with respect to the vertical. m 10Help me please
- A simple pendulum is swinging back & forth through a small angle, its motion repeating every 1.31 s. How much longer should the pendulum be made in order to increase its period by 0.26s ?An object of mass 1,996kg is attached to a spring with a spring constant of 3.53 x 10^5 N/m. Suppose the mass is pulled to the left and released to set it into oscillation l. Calculate the frequency of oscillation.If the period of a simple pendulum is to be 4.55 s, what should be its length ?