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If an object is moved a distance D in the direction of an applied constant force F, then the work W done by the force is defined as W= FD If an object is moved along a straight line by a continuously varying force F(x) then the work W done by the force as the object moved from x=a to x=b is W =S, F(x)dx Work as the summation of increments are, • AW = force (Distance Increments) = F(Ax) and AW = force Increments (Distance) = F(Ax). Solve with solution: 1. A force of 750 pounds compresses a spring 3 inches from its natural length of 15 inches. Find the work done on compressing the spring an additional 3 inches.

If an object is moved a distance D in the direction of an applied constant force F, then the work W done by the force is defined as W= FD If an object is moved along a straight line by a continuously varying force F(x) then the work W done by the force as the object moved from x=a to x=b is W =S, F(x)dx Work as the summation of increments are, • AW = force (Distance Increments) = F(Ax) and AW = force Increments (Distance) = F(Ax). Solve with solution: 1. A force of 750 pounds compresses a spring 3 inches from its natural length of 15 inches. Find the work done on compressing the spring an additional 3 inches.

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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If an object is moved a distance D in the direction of an applied constant force F, then the work W done by the force is defined as W = FD If an object is moved along a straight line by a continuously varying force F(x) then the work W done by the force as the object moved from x=a to x=b is W =J" F (x)dx a Work as the summation of increments are, = force (Distance Increments) = F(Ax) and AW = force Increments (Distance) = F(Ax). AW || %3| Solve with solution: 1. A force of 750 pounds compresses a spring 3 inches from its natural length of 15 inches. Find the work done on compressing the spring an additional 3 inches.
Transcribed Image Text:If an object is moved a distance D in the direction of an applied constant force F, then the work W done by the force is defined as W = FD If an object is moved along a straight line by a continuously varying force F(x) then the work W done by the force as the object moved from x=a to x=b is W =J" F (x)dx a Work as the summation of increments are, = force (Distance Increments) = F(Ax) and AW = force Increments (Distance) = F(Ax). AW || %3| Solve with solution: 1. A force of 750 pounds compresses a spring 3 inches from its natural length of 15 inches. Find the work done on compressing the spring an additional 3 inches.
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