A metal tank wheel in the shape of a disc of radius R is lightened by cutting out six identical through- holes in the shape of discs, whose axes are parallel to the wheel’s axis of rotation, and whose radii are all r. The holes’ centers are positioned at the vertices of a regular hexagon of side A, with the wheel’s axis passing through the center of the hexagon. By what percentage is the wheel’s moment of inertia decreased around its rotation axis, as a result of the cut outs, for r=R/5 and A=3R/4. Is the solution: 27.95% (using negative mass for cutouts and parallel axis theorem)?

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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Steiner’s theorem and gyration radius. A metal tank wheel in the shape of a disc of radius R is lightened by cutting out six identical through- holes in the shape of discs, whose axes are parallel to the wheel’s axis of rotation, and whose radii are all r. The holes’ centers are positioned at the vertices of a regular hexagon of side A, with the wheel’s axis passing through the center of the hexagon. By what percentage is the wheel’s moment of inertia decreased around its rotation axis, as a result of the cut outs, for r=R/5 and A=3R/4. Is the solution: 27.95% (using negative mass for cutouts and parallel axis theorem)?
Expert Solution
Step 1

Given data:

Radius of disc = R

Radius of hole = r = R/5

Side of regular hexagon = A = 3R/4

We have to find the change in moment of inertia of the wheel due to the cut outs of hole placed at the vertices of the regular hexagon.

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