The problem describes a scenario where an individual is belaying a child. The rope is wrapped around a drum for two full rotations and positioned at an angle \( \Theta = 49^\circ \). The question asks for the minimum force required to keep the child from falling if they weigh \( W = 89 \) lb.### Diagram Explanation:- **Left Side**: The individual is holding the rope.- **Right Side**: The child is attached to the rope.- **Drum**: The rope is wrapped around this drum, illustrating the path of the rope.- **Rope**: The red line represents the rope path. It extends from the child, wraps around the drum, and is held by the individual.- **Angle \( \Theta \)**: The angle of the rope around the drum is given as 49°.This setup suggests a physics problem involving tension, friction, and forces.

Given: The angle θ is 49o. The weight of the child is 89 lb. Consider the figure,The formula to calculate the force applied to the rope is, WP=eμβ Here, W is the weight of the child, P is the force applied, μ is the coefficient of friction, and β is the angle by which the rope is wrapped on the drum.Assume the coefficient of friction is 0.3. Calculate the angle by which rope is wrapped on the drum. β=3×2π-41°×π180°=5.77π Calculate the force applied to the rope. WP=eμβ89P=e0.35.77πP=89e0.35.77π=0.387 lbAnswer: The force applied to the rope is 0.387 lb.