If a solution containing 45.10 g of mercury(II) nitrate is allowed to react completely with a solution containing 12.026 g of sodium sulfate according to the equation below. Hg(NO3)2(aq) + Na2SO4(aq) → 2 NaNO3(aq) + HgSO4(s) How many grams of solid precipitate will be formed? How many grams of the reactant in excess will remain after the reaction?

If a solution containing 45.10 g of mercury(II) nitrate is allowed to react completely with a solution containing 12.026 g of sodium sulfate according to the equation below. Hg(NO3)2(aq) + Na2SO4(aq) → 2 NaNO3(aq) + HgSO4(s) How many grams of solid precipitate will be formed? How many grams of the reactant in excess will remain after the reaction?

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

What mass of precipitate (in g) is formed when 45.5 mL of 0.300 M Li₃PO₄ reacts with 50.5 mL of 0.200 M CrCl₃ in the following chemical reaction? Li₃PO₄(aq) + CrCr₃(aq) → CrPO₄(s) + 3 LiCl(aq)
Use the equation 6KI (aq) + 8HNO3 (aqg) → 6KNO3 (aq) + 2NO (g)+ 312 (9) +4H20 ()- If 21.38 mL of 0.787 M KI are reacted, how many molecules of I2 will be produced?
What quantity in moles of precipitate will be formed when 87.6 mL of 0.150 M AgNO₃ is reacted with excess CaCl₂ in the following chemical reaction? 2 AgNO₃(aq) + CaCl₂(aq) → 2 AgCl(s) + Ca(NO₃)₂(aq)
What mass of precipitate (in g) is formed when 45.5 mL of 0.300 M Li₃PO₄ reacts with 56.0 mL of 0.200 M CrCl₃ in the following chemical reaction? Li₃PO₄(aq) + CrCr₃(aq) → CrPO₄(s) + 3 LiCl(aq)
What is the mass in grams of precipitate formed when 45.5 mL of 0.300 M Na₃PO₄ reacts with 59.0 mL of 0.200 M Cr(NO₃)₃ in the following chemical reaction? Na₃PO₄ (aq) + Cr(NO₃)₃ (aq) → CrPO₄ (s) + 3 NaNO₃ (aq)
1 What quantity in moles of precipitate are formed when 35.0 mL of 0.350 M CaCl₂ is mixed with excess Na3PO4 in the following chemical reaction? 3 CaCl₂(aq) + 2 Na3PO4(aq) → Ca3(PO4)2 (s) + 6 NaCl(aq) ! Q CEL JUL 25 F1 SABORUMUNE 12 952 2 W F2 # 3 80 E F3 79 $ 4 16 DO 000 F4 R DI % 5 F5 T stv 6 SA MacBook Air F6 Y & 7 F7 U ▶II * 00 8 F8 W 1
How many moles of precipitate will be formed when 75.0 mL of 2.00 M NaCl is reacted with 200.0 mL of 0.600 M Pb(NO₃)₂ in the following chemical reaction? 2 NaCl(aq) + Pb(NO₃)₂(aq) → PbCl₂(s) + 2 NaNO₃(aq)
For the following reaction, 72.0 grams of barium chloride are allowed to react with 64.0 grams of potassium sulfate. barium chloride(aq) + potassium sulfate(aq) →→→→→barium sulfate(s) + potassium chloride (aq) What is the maximum amount of barium sulfate that can be formed? grams What is the FORMULA for the limiting reagent? What amount of the excess reagent remains after the reaction is complete? grams
What mass of precipitate (in g) is formed when 45.5 mL of 0.300 M K₃PO₄ reacts with 54.5 mL of 0.200 M CrCl₃ in the following chemical reaction? K₃PO₄(aq) + CrCl₃(aq) → CrPO₄(s) + 3 KCl₃(aq)
A chemist prepares a solution of iron(II) bromide (FeBr,) by measuring out 97.1 mg of FeBr, into a 100. mL volumetric flask and filling to the mark with distilled water. Calculate the molarity of Br anions in the chemist's solution. Be sure your answer is rounded to 3 significant digits. olo mol x10 Ar
What mass of precipitate (in g) is formed when 45.5 mL of 0.300 M Li₃PO₄ reacts with 41.5 mL of 0.200 M Cr(NO₃)₃ in the following chemical reaction? Li₃PO₄(aq) + Cr(NO₃)₃(aq) → CrPO₄(s) + 3 LiNO₃(aq)
Determine the mass of precipitate, in grams, that forms when 81.9 mL of 0.0609 M Ba(ClO4)2 reacts with 95.2 mL of 0.0336 M K2SO4. Ba(ClO4)2(aq) + K2SO4(aq) → 2KClO4(aq) + BaSO4(s)