If a reversed curve with two parallel tangents of equal radii equal to 280m, with an intermediate tangent of 280m and the horizontal distance of the PC & PT measured parallel to the tangent is 780m, compute the stationing of the PT if PC is at station 8 + 750.35. PC is at upper tangent.

If a reversed curve with two parallel tangents of equal radii equal to 280m, with an intermediate tangent of 280m and the horizontal distance of the PC & PT measured parallel to the tangent is 780m, compute the stationing of the PT if PC is at station 8 + 750.35. PC is at upper tangent.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

q4. #2
Two tangents converge at an angle of 30°, the direction of the second tangent is due east. The vertical distance of the PC from the second tangent is 116.50. The bearing of the common tangent is S 40° E. a) Compute the central angle of the first curve. b) If a reversed curve is to connect these two tangents, determine the common radius of the curve. c) Compute the stationing of the PT if PC is located at 10+620.
Two tangents adjacent to each other having bearings N 66 E and S 81 E meet at station 11+150.If the radius of the simple curve connecting these two tangents is 261 m, determine the lengthof the curve and the external distance.
10-1. A simple horizontal curve of radius 750' connects two tangents that intersect at an angle of 66° 30’ Compute T, L, LC, E, and M. 10-3. What is the degree of curve (using the arc definition) in problem #1? 10-5. A simple curve is to be laid out so that its middle ordinate is at least 75'. If the tangents intersect at an angle of 40°, what is the highest degree of curve that can be used? 10-7. The radius of a simple curve is twice its tangent distance. What is the angle of intersection? 10-9. For the simple curve in problem #1, if the station of the PI is 22+50, what are the stations of the PC and PT?
Two tangents converge at an angle 26.7 degrees, which were connected by a reverse curve. The direction of the second tangent is due to East which is having the shortest distance to the point PRC of 134.02 meters. What is the value of the total curve in meters if the bearing of the common tangent is S 35.6 E. Take into consideration that the length of the first tangent is one third the length of the second tangent. Station PC is at Sta 10+620.
Two tangents adjacent to each other having bearings N 65 E and S 81 E meet at station 11+150. If the radius of the simple curve connecting these two tangents is 251 m, determine the following A. Tangent Distance B. Length of curve C. Station of PT
Two tangents that intersect at an angle of 40º40’ are to be connected by a compound curve consisting of a 4.1º curve and a 5.5º curve. If the tangent at the beginning of the curve to the point of intersection of the tangent is 110m long, Compute the central angle of the first curve, I1. Compute the central angle of the second curve, I2. Compute the length of the tangent from the end of the 5.5º-curve to the point of intersection of the tangents.
A. Reversed curve with diverging tangents is to pass through three lines to form a center line of a proposed road. the first line AB has a bearing of N 88° E. and a distance of 125 m., BC has a bearing of N 60° E and a distance of 350 m., while on that of CD has a bearing of S 40° E and a distance of 305 m. If the first tangent has a distance of only % of the common tangent measured from the point of intersection of the first curve determine the radius of the curves and station of PT if PC is 12 + 350
A reverse curve with diverging tangent is to be designed for a proposed highway as illustrated below. The reverse curve is composed of one compound curve, from point A to C, and one simple curve, from point C to D. Point A is located at the Point of Curvature having Station 12+808.35, point B is located at the Point of Compound Curve, point C is located at the Point of Tangency. The back tangent of the reverse curve is having an located at the Point of Reverse Curve, and point D azimuth of 388.5 degrees and the forward tangent is having an azimuth of 748.8 degrees. The common tangent for the reverse curve has an azimuth of 313.1 degrees from south. It has been found out that the long chord of curve A to C is thrice the value of the chord in curve C to D. The common tangent of the curve A to C is having an azimuth of 254.1 degrees from south and the chord of curve C to D is 161.3m long.
Two parallel tangents have directions of due east and are 200 m, apart, are connected by a reversed curve having an equal radius of 800 m. The P.C. of the curve is on the upper tangent while the PT. is at the lower tangent. If the horizontal distance parallel to the tangent from the PC to the PT of the reversed curve is 800 m. a. Compute the distance of the intermediate tangent between the curves. b. Compute the distance between the centers of the reversed curve. c. Compute the stationing of PT. if sta: of the P. C. is 10 +020.40.