If a neutron star has a radius of 9.12 km and a temperature of 3.63 x 106 K, how luminous is it in watts? w How does its luminosity compare to the Sun (3.83 x 1026 w)? Lsun

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Chapter1: Units, Trigonometry. And Vectors
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**Problem Statement:**

If a neutron star has a radius of 9.12 km and a temperature of \(3.63 \times 10^6\) K, how luminous is it in watts?

- [Input Box] W

How does its luminosity compare to the Sun (\(3.83 \times 10^{26}\) W)?

\[
\frac{L_*}{L_{\text{Sun}}} = 
\]

**Instructions:**

1. **Calculate Luminosity:**
   - Use the formula for luminosity \(L = 4 \pi R^2 \sigma T^4\), where \(R\) is the radius, \(\sigma\) is the Stefan-Boltzmann constant, and \(T\) is the temperature.
   - Substitute the given values to find the luminosity in watts.

2. **Compare Luminosity to the Sun:**
   - Divide the calculated luminosity of the neutron star by the Sun’s luminosity to find the ratio \(\frac{L_*}{L_{\text{Sun}}}\). 

**Note:**
This section allows learners to understand the basic concepts of stellar luminosity and perform calculations comparing different stellar objects.
Transcribed Image Text:**Problem Statement:** If a neutron star has a radius of 9.12 km and a temperature of \(3.63 \times 10^6\) K, how luminous is it in watts? - [Input Box] W How does its luminosity compare to the Sun (\(3.83 \times 10^{26}\) W)? \[ \frac{L_*}{L_{\text{Sun}}} = \] **Instructions:** 1. **Calculate Luminosity:** - Use the formula for luminosity \(L = 4 \pi R^2 \sigma T^4\), where \(R\) is the radius, \(\sigma\) is the Stefan-Boltzmann constant, and \(T\) is the temperature. - Substitute the given values to find the luminosity in watts. 2. **Compare Luminosity to the Sun:** - Divide the calculated luminosity of the neutron star by the Sun’s luminosity to find the ratio \(\frac{L_*}{L_{\text{Sun}}}\). **Note:** This section allows learners to understand the basic concepts of stellar luminosity and perform calculations comparing different stellar objects.
Expert Solution
Step 1

1)Using stefan's lawP = σ A T4Where P is the power σ is the stefan's constant Ais the area of surface T is the temperature of the surfaceP = 5.67 * 10-8  *π*(9120)2 * (3.63*106)4 P = 2.57 *1027 W

 

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