If a line is parallel to the vector 7i + 5j+ 5k and passes through the point P=(4,3,5), then the parametric equation of the line is : O a. X=4-7A, Y= 3- 51, Z= 5-5A а. O b. X=-4+ 7A, Y= -3+ 51, Z= -5+5A O c. X=4+ 7A, Y= 3+ 5A, Z= 5+5A O d. X=-4-7A, Y=- 3- 51, Z= -5-5A

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A: Direction ratio is = (6-0, 6-0)= (6,6) That is equivalent to (1,1) , (2,2) and (3,3)

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A: Once we get vector form of the equation we can easily write the parametric form of equation of line.

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A: It is three dimensional, so each points must have three components (x,y,z).

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A: Solution

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A: note : as per company guidelines we support one question in one request. kindly repost next question…

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