If a graph is a parabola ['horseshoe' shape] opening up with a vertex [starting point] at (-5, -7) that only crosses the y-axis once at (0,18) and crosses the x-axis at both (-7.65,0) and at (-2.35,0): find the quadratic function for this graph, using the form f (x) = a(x – h)² + k, with a = 1 here. %3D O f(z) = (1 – 5)² + 7 O f(x) = (x + 7.65)² – 2.35 O f(z) = (z – 5)² – 7 O f(z) = (1 + 5) +7 O f(z) = (z + 5)² - 7

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