A. y = - (x – 2)2 B. y = -(x - 2)2 C. y = (x + 2)? D. y = -(x + 2)² 7. A. y = -4(x + 2)² + 1 B. y = -4(x – 2)² – 1 C. y = 4(x – 2)² +1 D. y = 4(x – 2)² – 1 8.
A. y = - (x – 2)2 B. y = -(x - 2)2 C. y = (x + 2)? D. y = -(x + 2)² 7. A. y = -4(x + 2)² + 1 B. y = -4(x – 2)² – 1 C. y = 4(x – 2)² +1 D. y = 4(x – 2)² – 1 8.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
Identify the quadratic function using the graphs below. The other picture is an example of it.
Transcribed Image Text:* Follow This One!
Study the graph of the quadratic function below. Determine the equation
given in the graph by following the steps below.
1. Identify the vertex (h, k)
2. Identify the coordinates of
any point on the parabola.
3. Substitute the vertex (h, k)
and coordinates of any
point (x,y)into the vertex
form y = a(x - h)² + k.
4. Get the value of a.
5. Write the equation of the
quadratic function.
* Try to Understand!
When the vertex and any point on the parabola are clearly seen, the
equation of the quadratic function can be determined by using the form of a
quadratic function y = a(x – h)² + k.
Do the "Follow This One!" activity above. The vertex of the graph of
the quadratic function is (4, –2). The graph passes through the point (2,0). By
11
replacing x and y with 2 and 0, respectively, and h and k with 4 and -2
respectively, we have
y = a(x – h)² + k
(0) = a(2 – 4)² +(-2)
0 %3D 4а — 2
4а 2
Substitute the vertex and
Substitute the vertex, h=4, k=-
2 and the value of a=̟ to y =
a(x – h)² + k form the
required quadratic function
y = a(x – h)² + k
the x-intercept
Simplify
Divide both sides
-=
by 4
1
a =
2
y = ;
r– 4)² – 2
Thus, the quadratic equation is y ==(x – 4)² – 2.
Transcribed Image Text:A. y =(x – 2)2
B. y = -(x – 2)?
C. y = « + 2)*
D. y = -(x + 2)²
7.
-3
A. y = -4(x +2)² + 1
B. y = -4(x – 2)² – 1
C. y = 4(x – 2)² +1
D. y = 4(x – 2)² – 1
8.
2.
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