If a gaseous mixture is made by combining 1.29 g Ar and 2.46 g Kr in an evacuated 2.50 L container at 25.0 °C, what are the partial pressures of each gas, PAr and PKr, and what is the total pressure, Protal, exerted by the gaseous mixture? PAr = atm PKr = atm Potal = atm
If a gaseous mixture is made by combining 1.29 g Ar and 2.46 g Kr in an evacuated 2.50 L container at 25.0 °C, what are the partial pressures of each gas, PAr and PKr, and what is the total pressure, Protal, exerted by the gaseous mixture? PAr = atm PKr = atm Potal = atm
Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter5: Gases
Section: Chapter Questions
Problem 5.101PAE
Related questions
Question
![If a gaseous mixture is made by combining 1.29 g Ar and 2.46 g Kr in an evacuated 2.50 L container at 25.0 °C, what are the partial pressures of each gas, \( P_{\text{Ar}} \) and \( P_{\text{Kr}} \), and what is the total pressure, \( P_{\text{total}} \), exerted by the gaseous mixture?
\[ P_{\text{Ar}} = \] atm
\[ P_{\text{Kr}} = \] atm
\[ P_{\text{total}} = \] atm](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4cbada35-3122-4a6c-a25c-246bca0ae236%2Fa3285ac1-a8d9-4367-b54e-873711b9d5c5%2Ftk550f_processed.png&w=3840&q=75)
Transcribed Image Text:If a gaseous mixture is made by combining 1.29 g Ar and 2.46 g Kr in an evacuated 2.50 L container at 25.0 °C, what are the partial pressures of each gas, \( P_{\text{Ar}} \) and \( P_{\text{Kr}} \), and what is the total pressure, \( P_{\text{total}} \), exerted by the gaseous mixture?
\[ P_{\text{Ar}} = \] atm
\[ P_{\text{Kr}} = \] atm
\[ P_{\text{total}} = \] atm
Expert Solution

Step 1
The total pressure of a mixture of two non reacting gases is given by
PtotalV = (n1+n2)RT
Ptotal = total pressure
V = volume
n1 , n2 are number of moles of two gases
R = 0.08206 L•atm/mol•K
T = Temperature in Kelvin
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