If a gaseous mixture is made by combining 1.29 g Ar and 2.46 g Kr in an evacuated 2.50 L container at 25.0 °C, what are the partial pressures of each gas, PAr and PKr, and what is the total pressure, Protal, exerted by the gaseous mixture? PAr = atm PKr = atm Potal = atm

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter5: Gases
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If a gaseous mixture is made by combining 1.29 g Ar and 2.46 g Kr in an evacuated 2.50 L container at 25.0 °C, what are the partial pressures of each gas, \( P_{\text{Ar}} \) and \( P_{\text{Kr}} \), and what is the total pressure, \( P_{\text{total}} \), exerted by the gaseous mixture?

\[ P_{\text{Ar}} = \]  atm

\[ P_{\text{Kr}} = \]  atm

\[ P_{\text{total}} = \]  atm
Transcribed Image Text:If a gaseous mixture is made by combining 1.29 g Ar and 2.46 g Kr in an evacuated 2.50 L container at 25.0 °C, what are the partial pressures of each gas, \( P_{\text{Ar}} \) and \( P_{\text{Kr}} \), and what is the total pressure, \( P_{\text{total}} \), exerted by the gaseous mixture? \[ P_{\text{Ar}} = \] atm \[ P_{\text{Kr}} = \] atm \[ P_{\text{total}} = \] atm
Expert Solution
Step 1

The total pressure of a mixture of two non reacting gases is given by 

PtotalV = (n1+n2)RT 

Ptotal = total pressure 

V = volume 

n1 , n2 are number of moles of two gases

R = 0.08206 L•atm/mol•K

T = Temperature in Kelvin

 

 

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