If a galaxy contains a supernova that at its brightest has an apparent magnitude of +21, how far away is the galaxy? Assume that the absolute magnitude of the supernova is -17. (Hint: Use the magnitude-distance formula: d = 10(mv - My + 5)/5 :) | Мрс

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**Problem Statement:**

If a galaxy contains a supernova that at its brightest has an apparent magnitude of +21, how far away is the galaxy? Assume that the absolute magnitude of the supernova is -17. 

*(Hint: Use the magnitude-distance formula: \( d = 10^{\frac{(m_V - M_V + 5)}{5}} \).)*

**Solution:**

Use the provided formula to calculate the distance \( d \) in Megaparsecs (Mpc).

**Formula Breakdown:**

- \( m_V \): The apparent magnitude of the supernova (+21 in this case).
- \( M_V \): The absolute magnitude of the supernova (-17 in this case).
- Insert these values into the formula to find \( d \).

Graph or Diagram Explanation: 

There is no graph or diagram in this image.
Transcribed Image Text:**Problem Statement:** If a galaxy contains a supernova that at its brightest has an apparent magnitude of +21, how far away is the galaxy? Assume that the absolute magnitude of the supernova is -17. *(Hint: Use the magnitude-distance formula: \( d = 10^{\frac{(m_V - M_V + 5)}{5}} \).)* **Solution:** Use the provided formula to calculate the distance \( d \) in Megaparsecs (Mpc). **Formula Breakdown:** - \( m_V \): The apparent magnitude of the supernova (+21 in this case). - \( M_V \): The absolute magnitude of the supernova (-17 in this case). - Insert these values into the formula to find \( d \). Graph or Diagram Explanation: There is no graph or diagram in this image.
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