If a galaxy contains a supernova that at its brightest has an apparent magnitude of +21, how far away is the galaxy? Assume that the absolute magnitude of the supernova is -17. (Hint: Use the magnitude-distance formula: d = 10(mv - My + 5)/5 :) | Мрс
If a galaxy contains a supernova that at its brightest has an apparent magnitude of +21, how far away is the galaxy? Assume that the absolute magnitude of the supernova is -17. (Hint: Use the magnitude-distance formula: d = 10(mv - My + 5)/5 :) | Мрс
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Transcribed Image Text:**Problem Statement:**
If a galaxy contains a supernova that at its brightest has an apparent magnitude of +21, how far away is the galaxy? Assume that the absolute magnitude of the supernova is -17.
*(Hint: Use the magnitude-distance formula: \( d = 10^{\frac{(m_V - M_V + 5)}{5}} \).)*
**Solution:**
Use the provided formula to calculate the distance \( d \) in Megaparsecs (Mpc).
**Formula Breakdown:**
- \( m_V \): The apparent magnitude of the supernova (+21 in this case).
- \( M_V \): The absolute magnitude of the supernova (-17 in this case).
- Insert these values into the formula to find \( d \).
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