If A, B, and C are any three events, then P(AU BUC) = P(A) + P(B) + P(C) - P(An B) -P(An C) - P(B n C) + P(An BnC).
If A, B, and C are any three events, then P(AU BUC) = P(A) + P(B) + P(C) - P(An B) -P(An C) - P(B n C) + P(An BnC).
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Can you please help me with this because I am so confused by it can you please do this problem step by step so I can follow along. Thank you so much

Transcribed Image Text:If A, B, and C are any three events, then
P(AU BUC) = P(A) + P(B) + P(C) - P(An B)
-P(An C) - P(Bn C) + P(An Bn C).
1.2-1. A combination lock was left at a fitness center. The correct combination is a three-
digit number d₁d2d3, where di, i = 1, 2, 3, is selected from 0, 1, 2, 3, ..., 9. How many
different lock combinations are possible with such a lock?
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