If a = 3.0 mm, b = 4.0 mm, Q, = 60 nC, Q2 = -80 nC, and q = 36 nC in the figure, what is the magnitude of the total electric force on q? Answer = 3.8 N a b Q1

University Physics Volume 2
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ISBN:9781938168161
Author:OpenStax
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Chapter5: Electric Charges And Fields
Section: Chapter Questions
Problem 82P: Two thin conducting plates, each 25.0 cm on a side, are situated parallel to one another and 5.0 mm...
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Can you please help with this and show the steps to solve please? Thank you Bartelby! 

If a = 3.0 mm, b = 4.0 mm, Q, = 60 nC, Q, = -80 nC, and q = 36 nC in the figure, what is
the magnitude of the total electric force on q? Answer = 3.8 N
a
b
Q1
Transcribed Image Text:If a = 3.0 mm, b = 4.0 mm, Q, = 60 nC, Q, = -80 nC, and q = 36 nC in the figure, what is the magnitude of the total electric force on q? Answer = 3.8 N a b Q1
Expert Solution
Step 1

Working formula:

According to Coulomb's law the magnitude of electrostatic force between two charges of magnitude q1 & q2 and separated by a distance of r is

F=kq1q2r2       ...(1)

where k is the Coulomb constant

k=9×109 in SI unit

If the sign of the two charges is the same then they repel each other & if the sign of the two charges is opposite then they attract each other.

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